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Greeley [361]
3 years ago
5

A club with thirteen members is to choose three​ officers: ​ president, vice-president, and​ secretary-treasurer. If each office

is to be held by one person and no person can hold more than one​ office, in how many ways can those offices be​ filled?
Mathematics
1 answer:
tatiyna3 years ago
4 0

Answer:

hope this helps

Step-by-step explanation:

so there are 10 choices for president

then after that there are 9 choices for VP

then afte P and VP there are 8 choices for Treasurer

and finally after P, VP and T, there are 7 choices left for Secretary.

So the number of ways to fill those offices with 10 candidates is

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Answer:

0, 10

Step-by-step explanation:

The given function is:

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Applying the quotient rule:

g(y) = \frac{y-5}{y^2-3y+15}\\g'(y)=\frac{(y-5)*(2y-3)-(y^2-3y+15)*(1)}{(y^2-3y+15)^2}

The values for which g'(y) are zero are the critical points:

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The critical values are y = 0 and y = 10.

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Lesechka [4]

Answer:

i think the answer is 23

Step-by-step explanation:

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8 0
3 years ago
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