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Sholpan [36]
3 years ago
12

Help please answers helllllllp

Mathematics
2 answers:
Bess [88]3 years ago
8 0
P = 0 because zero is to the right of -12 so it makes it greater and the other numbers are to the left of -12 so they’re less than so basically the answer is zero
Akimi4 [234]3 years ago
4 0

Answer:

p = 0

Step-by-step explanation:

We know that p = 0 because it is great than negative 12.

When a number is negative that means that it is less than zero.

The options listed are:

-18, -15, -20, 0, -13

Now a lot of people get confused about this. However, since these numbers are <em>less than</em> zero it means that these numbers are getting further and further away from a whole number.

So, as these numbers appear to be getting bigger they are actually getting smaller.

So, the only number that is greater than -12, of the options that you have, is 0!

<em>Final Answer: </em>p = 0

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8 0
3 years ago
Peter paid $79.80 for renting a tricycle for 6 hours. What was the rate per hour for renting the tricycle? (Input only numeric v
inn [45]
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Answer:

15

Step-by-step explanation:

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3 0
3 years ago
Hank's gas tank holds 18.5 gallons. If the tank has 6 gallons of gasoline in it, what percent of the tank is empty?
sergij07 [2.7K]

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8 0
3 years ago
Read 2 more answers
6. (09.04 LC)
anzhelika [568]

Given:

The quadratic equation is

y=6x^2-9x+22

To find:

The correct application of the quadratic formula.

Solution:

If a quadratic equation is ax^2+bx+c=0, then the quadratic formula is

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

We have,

y=6x^2-9x+22

Putting y=0, we get

6x^2-9x+22=0

Here, a=6,b=-9,c=22. Using the quadratic formula, we get

x=\dfrac{-(-9)\pm \sqrt{(-9)^2-4(6)(22)}}{2(6)}

The correct application of the quadratic formula is x=\dfrac{-(-9)\pm \sqrt{(-9)^2-4(6)(22)}}{2(6)}.

Note: The options are not in proper format.

8 0
3 years ago
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