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riadik2000 [5.3K]
4 years ago
15

A technician is troubleshooting a small network with cable Internet service in which a user is receiving a message in her web br

owser stating a site cannot be found. While interviewing users, it is determined that every host on the network is experiencing the same issue with all websites. Which of the following is the first step in troubleshooting this issue?
a. Use a cable tester to test the patch cable for the first user who reported the issue.
b. Reboot the soho router connecting the lan to the cable modem.
c. Call the internet service provider and report the problem.
d. Replace the patch cable from the soho router to the cable modem.
e. Connect a computer directly to the cable modem and attempt to access the internet.
Computers and Technology
1 answer:
expeople1 [14]4 years ago
6 0

Answer:

Option E is correct.

Explanation:

A professional is fixing a cable internet access network by which a person in their internet browser receives a text saying that a link could not be reached. It would be known that each and every server along the network is having the individual problem across whole websites when interviewing a person.

So, connect the system to the wired connection directly, & try to access the internet for troubleshooting the following issue.

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Which type of systems development is characterized by significantly speeding up the design phase and the generation of informati
nydimaria [60]

Answer:

Joint Application Development (JAD)

Explanation:

Joint Application Development is a method of application development that  lay emphasis on the up-front aspect of the application development cycle whereby steady communication between the designers and the intended users of the application under development by coming together in collaborative workshop styled discussions known as JAD sessions involving the mediators, facilitator, observers, end users, experts, and developers. As such with JAD process application development result in fewer errors high quality and is completed in lesser time.

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Question 4 1 pts The following code could be rewritten using: if (x > 12): if (x < 34):​
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Answer:

if(x>12 || x<34)

Explanation:

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3 years ago
Assignment Background Video games have become an outlet for artists to express their creative ideas and imaginations and a great
Sphinxa [80]

Answer:

Code

import csv

def open_file():

try:

fname=input("Enter the filename to open (xxx.yyy): ")

fp=open(fname,encoding='utf-8')

return fp

except FileNotFoundError:

print("File not found! Please Enter correct filename with extension")

return open_file()

def read_file(fp):

fields = []

rows = []

csvreader = list(csv.reader(fp))

# skiped 1 row because it contains field name

fields = csvreader[0]

D1={}

D2={}

D3={}

# accessing the data of csv file

for line in csvreader[1:]:

name = line[0].lower().strip()

platform = line[1].lower().strip()

if line[2]!='N/A':

year = int(line[2])

else:

year=line[2]

genre = line[3].lower().strip()

publisher = line[4].lower().strip()

na_sales = float(line[5])

eur_sales = float(line[6])

jpn_sales = float(line[7])

other_sales = float(line[8])

global_sales=(na_sales+eur_sales+jpn_sales+other_sales)*1000000

if name not in D1:

D1[name]=[]

D1[name].append((name, platform, year, genre, publisher,global_sales))

if genre not in D2:

D2[genre]=[]

D2[genre].append((genre, year, na_sales, eur_sales,jpn_sales, other_sales, global_sales))

if publisher not in D3:

D3[publisher]=[]

D3[publisher].append((publisher, name, year, na_sales,eur_sales, jpn_sales, other_sales, global_sales))

# sorting

temp={}

# sorting keys

for Keys in sorted (D1) :

ls=D1[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

temp[Keys]=ls

D1=temp.copy()

temp={}

# sorting keys

for Keys in sorted (D2) :

ls=D2[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

temp[Keys]=ls

D2=temp.copy()

temp={}

# sorting keys

for Keys in sorted (D3) :

ls=D3[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

temp[Keys]=ls

D3=temp.copy()

return D1,D2,D3

 

def main():

fp=open_file()

D1,D2,D3=read_file(fp)

# displaying the row_count in dictionaries

cnt=0

for d in D1:

cnt+=1

print(cnt)

print("\n\n=============================================\n\n")

cnt=0

for d in D2:

cnt+=1

print(cnt)

print("\n\n=============================================\n\n")

cnt=0

for d in D3:

cnt+=1

print(cnt)

print("\n\n=============================================\n\n")

 

 

if __name__=="__main__":

main()

Explanation:

see code and see output attached

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