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topjm [15]
3 years ago
10

Write a program that computes the monthly net pay of the employee for a steel factory. The input for this program is the hourly

rate of pay, the number of regular and the overtime hour work. The tax-deductible rate is 20%. You need first to calculate the gross pay, which is the sum of the wages earned from regular hours and overtime hours, the overtime is paid at 1.5 times the regular rate. Then you subtract the tax from the gross pay to get the net pay of the employee.
Computers and Technology
1 answer:
Mars2501 [29]3 years ago
6 0

Answer:

#include<stdio.h>

int main()

{

float rate_of_pay,regular_hours,overtime_hours,grosspay,netpay,tax;

printf("Enter the Hourly rate of pay : ");

scanf("%f",&rate_of_pay);

printf("Enter the number of Regular hours : ");

scanf("%f",&regular_hours);

printf("Enter the number of Overtime hours : ");

scanf("%f",&overtime_hours);

grosspay=(regular_hours*rate_of_pay)+(1.5*overtime_hours*rate_of_pay);

netpay=grosspay-(grosspay*0.2);

printf("Employee's Gross pay = %f\n",grosspay);

printf("Tax = %f\n",0.2*grosspay);

printf("Employee's Net pay = %f\n",netpay);

return 0;

}

Note: The variables are declared as float, to support partial hours like 0.5,6.5 etc.

Explanation:

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From the binary search algorithm, it follows that every iteration of the while loop cuts the size of the search list by half.
Colt1911 [192]

Answer:

True: In binary search algorithm, we follow the below steps sequentially:

Input: A sorted array  B[1,2,...n] of n items and one item x to be searched.

Output: The index of x in B if exists in B, 0 otherwise.

  1. low=1
  2. high=n
  3. while( low < high )
  4.  {      mid=low + (high-low)/2
  5.         if( B[mid]==x)
  6.          {
  7.             return(mid)  //returns mid as the index of x
  8.           }
  9.          else
  10.          {
  11.              if( B[mid] < x)      //takes only right half of the array
  12.               {
  13.                 low=mid+1
  14.               }
  15.              else               // takes only the left half of the array
  16.               {
  17.                high=mid-1
  18.               }
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  20.  }
  21. return( 0 )

Explanation:

For each iteration the line number 11 or line number 15 will be executed.

Both lines, cut the array size to half of it and takes as the input for next iteration.

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