A two-digit number is twice the sum of its digit. If the tens digit is 7 less than the unit digit, find the number.
Let x= the unit digit
Then y= the tens digit
<span>And 10y+x= the number
</span>x+y= the sum of the digits
<span>Now we are told that 10y+x=2(x+y) ------1st equation </span>
<span>We are also told that y=x-7 ----------- 2nd Equation </span>
<span>So our equations to solve are: </span>
(1) 10y+x=2(x+y)
<span>(2) y=x-7
</span>
Hope it helps
The answer
<span>the third rope to counterbalance Sam and Charlie is F
and vectF +vectF1 +vectF2 =vect0
let's consider axis
y'y </span>vectF = -F
vectF 1= F1cos60
vectF 2= F2cos45
-F = -F1cos60-F2co45
so F= F1cos60+F2co45= 350x0.5+400x0.7=457.84 pounds
Answer:
Step-by-step explanation:
9. f(g(-n))
g(-n) = -(n²+5) = -n²-5
f(g(-n)) = 2n+1 (-n²-5 )
2n(-n²-5)+1(-n²-5 )
-2n³-10n-n²-5
-2n³-n²-10n-5
n²(-2n-1) +5(2n-1)
(n²+5)(2n-1)
10. (2x+2)(x³+3)
2x(x³+3)+2(x³+3)
2x⁴ + 2x³ +6x +6
2x³(x+1)+6(x+1)
(2x³+6)(x+1
There are 80.5 tens in 805
