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Degger [83]
3 years ago
13

The function below represents the interest Larissa earns on an investment. Identify the term that represents the amount of money

originally invested.
f(x) = 7,000(1 + 0.03)x

1
7,000
0.03
1.03
Mathematics
2 answers:
Ahat [919]3 years ago
7 0

Answer:

Option b

Step-by-step explanation:

Sergio039 [100]3 years ago
6 0

Option b: 7000

Explanation:

The function that Larissa earns on an investment is

f(x)=7000(1+0.03)^{x}

The amount of money originally invested by Larissa can be found using the compound interest formula,

f(x)=p(1+r)^{x}

where

P is the amount of money invested. (Principal)

r is the rate of interest which can be expressed as decimals.

x is the number of periods.

Hence, comparing f(x)=7000(1+0.03)^{x} with the formula f(x)=p(1+r)^{x}, the principal amount can be determined.

Thus, the principal amount is 7000.

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4> Solve by using Laplace transform: y'+5y'+4y=0; y(0)=3 y'(o)=o
harina [27]

Answer:

y=3e^{-4t}

Step-by-step explanation:

y''+5y'+4y=0

Applying the Laplace transform:

\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0

With the formulas:

\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)

\mathcal{L}[y']=s\mathcal{L}[y]-y(0)

\mathcal{L}[x]=L

s^2L-3s+5sL-3+4L=0

Solving for L

L(s^2+5s+4)=3s+3

L=\frac{3s+3}{s^2+5s+4}

L=\frac{3(s+1)}{(s+1)(s+4)}

L=\frac3{s+4}

Apply the inverse Laplace transform with this formula:

\mathcal{L}^{-1}[\frac1{s-a}]=e^{at}

y=3\mathcal{L}^{-1}[\frac1{s+4}]=3e^{-4t}

7 0
3 years ago
Give an example of a real number that is not rational.
Sever21 [200]

Answer:

A not rational number is called a irrational number btw. Anyway Some examples are √2 and pi.

7 0
3 years ago
Suppose that a manager is interested in estimating the average amount of money customers spend in her store. After sampling 36 t
musickatia [10]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The 90% confidence interval for this case would be (38.01, 44.29) and is given.

The best interpretation for this case would be: We are 90% confident that the true average is between $ 38.01 and $ 44.29 .

And the best option would be:

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

Step-by-step explanation:

Assuming this complete question: Which statement gives a valid interpretation of the interval?

The store manager is 90% confident that the average amount spent by the 36 sampled customers is between S38.01 and $44.29.

There is a 90% chance that the mean amount spent by all customers is between S38.01 and $44.29.

There is a 90% chance that a randomly selected customer will spend between S38.01 and $44.29.

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The 90% confidence interval for this case would be (38.01, 44.29) and is given.

The best interpretation for this case would be: We are 90% confident that the true average is between $ 38.01 and $ 44.29 .

And the best option would be:

The store manager is 90% confident that the average amount spent by all customers is between S38.01 and $44.29

8 0
3 years ago
Suppose that X1 and X2 are independent random variables each with a mean μ and a variance σ^2. Compute the mean and variance of
Deffense [45]

Mean:

E[Y] = E[3X₁ + X₂]

E[Y] = 3 E[X₁] + E[X₂]

E[Y] = 3µ + µ

E[Y] = 4µ

Variance:

Var[Y] = Var[3X₁ + X₂]

Var[Y] = 3² Var[X₁] + 2 Covar[X₁, X₂] + 1² Var[X₂]

(the covariance is 0 since X₁ and X₂ are independent)

Var[Y] = 9 Var[X₁] + Var[X₂]

Var[Y] = 9σ² + σ²

Var[Y] = 10σ²

5 0
3 years ago
The table shows the attendance at the art show for the past week.
Vinvika [58]

Answer:

D. 50

Step-by-step explanation:

7*30 - (54+29+22+28+12+15)

=210 - 160

=50

7 0
3 years ago
Read 2 more answers
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