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Butoxors [25]
3 years ago
10

Two mechanics worked on a car. the first mechanic worked for 10 hours, and the second mechanic worked for 15 hours. together the

y charged a total of $ 2500 . what was the rate charged per hour by each mechanic if the sum of the two rates was $ 205 per hour?
Mathematics
1 answer:
Yuliya22 [10]3 years ago
3 0
Let x and y be the rate per hour for Mechanic 1 and 2 respectively.

Then,
x+y=205 ---------- (1)
Additionally,
10x+15y = 2500 ------ (2)

Solving equations 1 and 2;
Multiply (1) by 10 and subtract two from the result,
10x+10y = 2050
10x +15 y =2500
----------------------
        -5 y = --450 => y = 450/5 = $90
Then,
x= 205-90 = $115

Therefore,
Mechanic 1 charged $115 per hour
Mechanic 2 charged $90 per hour
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3 years ago
Write as an ordered pair. 4x+2y=16 and -4y+x=4
Margaret [11]

Answer:

(4,0)

Step-by-step explanation:

4x+2y=16

-4y+x=4

Multiply the first equation by 2

2(4x+2y)=16*2

8x +4y = 32

Add the 2nd equation

8x +4y = 32

x  -4y     =4

--------------------

9x            =36

Divide each side by 9

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x=4

Now solve for y

-4y +x =4

-4y +4 = 4

Subtract 4 from each side

-4y +4-4=4-4

-4y =0

Divide by -4

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(4,0)

4 0
3 years ago
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iren2701 [21]
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7 0
3 years ago
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A farmer has 5 times as many cows as horses.
Assoli18 [71]

Answer:

The correct answer is !40 cows and 28 Horses

Step-by-step explanation:

h+5h=168

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h=168/6

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Proof:

28=140=168

168=168

7 0
3 years ago
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