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Butoxors [25]
3 years ago
10

Two mechanics worked on a car. the first mechanic worked for 10 hours, and the second mechanic worked for 15 hours. together the

y charged a total of $ 2500 . what was the rate charged per hour by each mechanic if the sum of the two rates was $ 205 per hour?
Mathematics
1 answer:
Yuliya22 [10]3 years ago
3 0
Let x and y be the rate per hour for Mechanic 1 and 2 respectively.

Then,
x+y=205 ---------- (1)
Additionally,
10x+15y = 2500 ------ (2)

Solving equations 1 and 2;
Multiply (1) by 10 and subtract two from the result,
10x+10y = 2050
10x +15 y =2500
----------------------
        -5 y = --450 => y = 450/5 = $90
Then,
x= 205-90 = $115

Therefore,
Mechanic 1 charged $115 per hour
Mechanic 2 charged $90 per hour
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svlad2 [7]

Answer:

B and C

Step-by-step explanation:

7 0
2 years ago
9/11 = ?/22<br> a. 12<br> b. 9<br> c. 4<br> d. 18
svlad2 [7]
18/22 = 2*9/2*11 = 9/11

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7 0
3 years ago
Military radar and missile detection systems are designed to warn a country of enemy attacks. A reliability question deals with
Nadusha1986 [10]

Answer:

Step-by-step explanation:

Given that a particular detection system has a 0.83 probability of detecting a missile attack.

Also each system is independent of the other to detect missile attack.

a)  the probability that a single detection system will detect an attack=0.83

b) the probability that at least one of the systems will detect the attack given two systems= 1-Prob no system detects

=1-(1-0.83)(1-0.83)\\\\=1-0.0289\\=0.9711

c)  If three systems are installed,  the probability that at least one of the systems  will detect the attack

= 1- none of the three systems detect attack

= (1-0.17^3)\\=1-0.004913\\=0.995087

d) We find that probability of detecting is more if we increase the system form 1 to 2 and 2 to 3.

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7 0
3 years ago
Plz help me with this math and also explain
jasenka [17]

Step-by-step explanation:

<h2>[1]</h2>

  • SI = $250
  • Rate (R) = 12\sf \dfrac{1}{2} %
  • Time (t) = 4 years

\longrightarrow \tt { SI = \dfrac{PRT}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 12\cfrac{1}{2} \times 4}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times \cfrac{25}{2} \times 4}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 25 \times 2}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 50}{100} } \\

\longrightarrow \tt { 250 \times 100 = P \times 50} \\

\longrightarrow \tt { 25000 = P \times 50} \\

\longrightarrow \tt { \dfrac{25000}{50} = P } \\

\longrightarrow \underline{\boxed{ \green{ \tt { \$ \; 500 = P }}}} \\

Therefore principal is $500.

<h2>__________________</h2>

<h2>[2]</h2>

  • 2/7 of the balls are red.
  • 3/5 of the balls are blue.
  • Rest are yellow.
  • Number of yellow balls = 36

Let the total number of balls be x.

→ Red balls + Blue balls + Yellow balls = Total number of balls

\longrightarrow \tt{ \dfrac{2}{7}x + \dfrac{3}{5}x + 36 = x} \\

\longrightarrow \tt{ \dfrac{10x + 21x + 1260}{35} = x} \\

\longrightarrow \tt{ \dfrac{31x + 1260}{35} = x} \\

\longrightarrow \tt{ 31x + 1260= 35x} \\

\longrightarrow \tt{ 1260= 35x-31x} \\

\longrightarrow \tt{ 1260= 4x} \\

\longrightarrow \tt{ \dfrac{1260 }{4}= x} \\

\longrightarrow \underline{\boxed{  \tt { 315 = x }}} \\

Total number of balls is 315.

A/Q,

3/5 of the balls are blue.

\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}x} \\

\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}(315)} \\

\longrightarrow \tt{ Balls_{(Blue)} = 3(63)} \\

\longrightarrow \underline{\boxed{ \green {\tt { Balls_{(Blue)} = 189 }}}} \\

8 0
3 years ago
Write an expression for "the product of 6 and q."<br> Please answer and not steal my points
AnnZ [28]

Answer:

6q

Step-by-step explanation:

5 0
3 years ago
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