Help me pls pls pls thanks I
1 answer:
You might be interested in
Answer:
There are 35 different sets of 3 books Joe could choose
Step-by-step explanation:
* Lets explain how to solve the problem
- Combination is a collection of the objects where the order doesn't
matter
- The formula for the number of possible combinations of r objects from
a set of n objects is nCr = n!/r!(n-r)!
- n! = n(n - 1)(n - 2)................. × 1
Lets solve the problem
- Joe has one book each for algebra, geometry, history, psychology,
Spanish, English and Physics in his locker
∴ He has <em>seven</em> books in the locker
- He wants to chose <em>three</em> of them
∵ The order is not important when he chose the books
∴ We will use the combination <em>nCr</em> to find how many different sets
of three books he can choose
- The total number of books is 7
∴ n = 7
∵ He chooses 3 of them
∴ r = 3
∵ 7C3 = 7!/3!(7 - 3)! = 7!/3!(4!)
∴
∴ 7C3 = 35
* There are 35 different sets of 3 books Joe could choose
Answer:
Gym A
Step-by-step explanation:
A linear relationship is a relationship of the form y = mx + b, where y and x are the linear variables, m is the rate of change and b is the value of y when x = 0.
Gym A:
Let x represent the month and y represent the total cost for the gym. From the table, we can represent the values in the form (x, y) as (1,70), (2, 90) and (3, 110). We can find the relationship between x and y using the formula:
Gym B:
We can represent the values from the table as (1,55), (2, 80) and (3, 105). We can find the relationship between x and y using the formula:
Hence gym A would cost less ($250 < $280)