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Alex Ar [27]
3 years ago
13

When something is melting is the energy going into the object or leaving the object

Chemistry
1 answer:
Reptile [31]3 years ago
8 0

Answer:

The energy is absorbed which causes an increase in kinetic energy of particles hence increase in temperature (which is defined as the average kinetic energy of particle) thereby causing melting

Hope this helps :)

I'd appreciate if you'd mark me brainliest because I've

been stuck on the same rank for wayyy too long :(

Goodluck! :)

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Copper wire is used in electrical wiring because the metallic bonding between the atoms aids with the ___________ of the materia
Darya [45]

electrons can move freely through the material

7 0
3 years ago
What are the regions of the spectrum with wavelengths that can pass through the atmosphere called?
motikmotik

Answer:

These regions of the spectrum with wavelengths that can pass through the atmosphere are referred to as "atmospheric windows." Some microwaves can even pass through clouds, which make them the best wavelength for transmitting satellite communication signals.

Explanation:

Hope this helps. Have a great rest of your day :)

4 0
3 years ago
If 1 mile = 5,280ft. how many miles are in 11,245ft​
slavikrds [6]
2.13 miles

You can also check it on google
3 0
4 years ago
How many grams of Na2SO4 will be formed from 200.0g of NaOH
nikklg [1K]

The question is incomplete, the complete question is;

Using the following equation 2 NaOH(aq) + H2SO4(aq) → 2 H2O(aq) + Na2SO4(aq) how many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid

Answer:

355.1 g

Explanation:

The equation of the reaction is;

2 NaOH(aq) + H2SO4(aq) → 2 H2O(aq) + Na2SO4(aq)

We have been told that H2SO4 is in excess so NaOH is the limiting reactant. Therefore;

Number of moles in 200g of NaOH = 200g/40g/mol = 5 moles

So;

2 moles of NaOH yields 1 mole of Na2SO4

5 moles of NaOH will yield 5 * 1/2 = 2.5 moles of Na2SO4

Molar mass of Na2SO4 = 142.04 g/mol

Mass of Na2SO4= 2.5 moles * 142.04 g/mol = 355.1 g

8 0
3 years ago
Consider the reaction: A <=> B. Under standard conditions at equiliubrium, the concentrations of the compounds are [A] = 1
Katen [24]

Answer:

Keq'>1\\\Delta G'

Explanation:

Hello,

In this case, for the given reaction, the equilibrium constant turns out:

Keq=\frac{[B]}{[A]}=\frac{0.5M}{1.5M} =1/3

Nonetheless, we are asked for the reverse equilibrium constant that is:

Keq'=\frac{1}{Keq}=3

Which is greater than one.

In such a way, the Gibbs free energy turns out:

\Delta G'=-RTln(Keq')\\

Now, since the reverse equilibrium constant is greater than zero its natural logarithm is positive, therefore with the initial minus, the Gibbs free energy is less than zero, that is, negative.

7 0
4 years ago
Read 2 more answers
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