All categories

3 years ago

Whats the longest word in history?

Chemistry

1 answer:

I am Lyosha [343]3 years ago

6 0

Answer:

Pneumonoultramicroscopicsilicovolcanoconiosis

Explanation:

You might be interested in

If an atom has 12 protons, 13 neutrons, and 10 electrons, what charge would the atom have?

andrew11 [14]

It would be a positive ion

3 0

3 years ago

I need numbers 8 and 9. Thank you.

Sophie [7]

313.110 for number 8

9) is 270.3003

hope this help!

5 0

3 years ago

If mass =180kg and volume =90m3, what is the density

DaniilM [7]

To find the density you must divide the mass by the density.
180kg ÷ 90m³ = 2kg/m³
The density is 2kg/m³

4 0

3 years ago

I need to check some chemistry questions. Help with any question is appreciated! :) Please include an explanation with your conc

finlep [7]

1. 4.67 kg; 2. 4.8 ×10^5 kg; 3. 0.106 cm^3; 4. 1.7 g/cm^3

Q1. Mass of Hg

Mass = 345 mL × (13.53 g/1 mL) = 4670 g = 4.67 kg

Q2. Mass of Pb

Step 1. Calculate the volume of the Pb.

V = lwh = 6.0 m × 3.5 m × 2.0 m = 42.0 m^3

Step 2. Calculate the mass of the Pb.

Mass = 42.0 m^3 × (11 340 kg/1 m^3) = 4.8 × 10^5 kg

Q3. Volume of displaced water

Volume of Ag = 0.987 g × (1 cm^3/9.320 g) = 0.106 cm^3

Archimedes: volume of displaced water = volume of Ag = 0.106 cm^3

4. Density of metal

Step 1. Convert ounces to grams

Mass = 3.35 oz × (28.35 g/1 oz) = 94.97 g

Step 2. Calculate the volume in cubic inches

V = lwh = 3.0 in × 2.5 in × 0.45 in = 3.38 in^3

Step 3. Convert cubic inches to cubic centimetres

V = 3.38 in^3 × (2.54 cm/1 in)^3 = 55.3 cm^3

Step 4. Calculate the density

ρ = m/V = (94.97 g/55.3 cm^3) = 1.7 g/cm^3 (magnesium?)

4 0

3 years ago

In IR spectroscopy, we normally talk about "frequencies" when in reality we are referring to wavenumbers. What is the mathematic

Svetach [21]

Answer:

Here's what I get.

Explanation:

(b) Wavenumber and wavelength

The wavenumber is the distance over which a cycle repeats, that is, it is the number of waves in a unit distance.

$\bar \nu = \dfrac{1}{\lambda}$

Thus, if λ = 3 µm,

$\bar \nu = \dfrac{1}{3 \times 10^{-6} \text{ m}}= 3.3 \times 10^{5}\text{ m}^{-1} = \textbf{3300 cm}^{-1}$

(a) Wavenumber and frequency

Since

λ = c/f and 1/λ = f/c

the relation between wavenumber and frequency is

$\bar \nu = \mathbf{\dfrac{f}{c}}$

Thus, if f = 90 THz

$\bar \nu = \dfrac{90 \times 10^{12} \text{ s}^{-1}}{3 \times 10^{8} \text{ m$\cdot$ s}^{-1}}= 3 \times 10^{5} \text{ m}^{-1} = \textbf{3000 cm}^{-1}$

(c) Units

(i) Frequency

The units are s⁻¹ or Hz.

(ii) Wavelength

The SI base unit is metres, but infrared wavelengths are usually measured in micrometres (roughly 2.5 µm to 20 µm).

(iii) Wavenumber

The SI base unit is m⁻¹, but infrared wavenumbers are usually measured in cm⁻¹ (roughly 4000 cm⁻¹ to 500 cm⁻¹).

8 0

3 years ago