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lilavasa [31]
3 years ago
8

Which classes of isomers are easier to separate from each other in the laboratory: enantiomers or diastereomers?

Chemistry
1 answer:
Varvara68 [4.7K]3 years ago
8 0

Answer:

diastereomers

Explanation:

Enantiomers are optical isomers that are mirror images of each other. Enantiomers can not be separated by physical methods because the both compounds have almost the same physical properties such as melting points, boiling points, etc. This makes it difficult to separate enanatiomers by conventional methods.

A common method of separating enantiomers is by converting them into diasteromers which are easily separated since diasteromers often have different chemical and physical properties.

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A reaction has a theoretical yield of 124.3 g SF6, but only 113.7 g SF6 are obtained in the lab, what is the percent yield of SF
ratelena [41]

Answer:

Percent yield = 91%

Explanation:

Given data:

Theoretical yield of SF₆ = 124.3 G

Actual yield of SF₆ = 113.7 g

Percent yield of SF₆ = ?

Solution:

Formula:

Percent yield = (actual yield / theoretical yield)× 100

By putting values,

Percent yield = (113.7 g/ 124.3 g) × 100

Percent yield = 0.91 × 100

Percent yield = 91%

6 0
3 years ago
Mark brainly if answered correctly
iren2701 [21]

ROW - ( 3 ) is correct

<u>SYSTEM</u><u> </u><u>(</u><u>A)</u>

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5 0
3 years ago
In a living organism, what is an organ? functional unit, or building block, of all organisms; smallest unit that can carry on th
ra1l [238]

Answer: D. a structure that provides a specific service within a cell​

Explanation:

7 0
2 years ago
A 25.225 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 75.815 g of wa
Rudik [331]

Answer:

1.43 (w/w %)

Explanation:

HCl reacts with NH3 as follows:

HCl + NH3 → NH4+ + Cl-

<em>1 mole of HCl reacts per mole of ammonia.</em>

Mass of NH3 is obtained as follows:

<em>Moles HCl:</em>

0.02999L * (0.1068mol / L) = 3.203x10-3 moles HCl = <em>Moles NH3</em>

<em>Mass NH3 in the aliquot:</em>

3.203x10-3 moles NH3 * (17.031g / mol) = 0.0545g.

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Dilution factor: 98.04g / 14.842g = 6.6056

That means mass of NH3 in the sample is:

0.0545g * 6.6056 = 0.36g NH3

Weight percent is:

0.36g NH3 / 25.225g * 100

<h3>1.43 (w/w %)</h3>
6 0
3 years ago
Coke is an impure form of carbon that is often used in the in-dustrial production of metals from their oxides. if a sample of co
olasank [31]
The reaction equation is:
<span>2CuO(s) + C(s) </span>→ <span>2Cu(s) + CO</span>₂<span>(g)

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The mass of coke required is 7.22 x 10⁴ grams
5 0
3 years ago
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