We are given the expression of the equation of a circle that is x2 + y2 + 14x + 2y + 14 = 0. Using ocmpleting the squares:
x2 + y2 + 14x + 2y + 14 = 0(x+7)^2 + (y+1) ^2 = -14 + 49 + 1(x+7)^2 + (y+1) ^2 = 36 center thus is at (-7,-1) and the radius is equal ot square root of 36 equal to 6.

7 0

3 years ago

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Need help with this ignore what a put in the box it isn’t right

Zarrin [17]

$f=6cm\\g=8cm$

Why?

The first thing we need to do is find the area of the triangle, we can to that by subtracting the area of ABCD from ACBE, then, we can use the formulas to calculate the area for both triangle and rectangle to find "f" and "g".

Calculating we have:

$TriangleArea=ABCE-ABCD\\\\TriangleArea=60cm^{2}-48cm^{2}=12cm^{2}$

Now, we can calculate "f" by using the formula to calculate the area of the triangle:

$TriangleArea=\frac{b*h}{2}\\\\TriangleArea=\frac{f*4cm}{2}\\\\12cm^{2}*2=f*4cm\\\\\frac{24cm^{2}}{4cm}=f\\\\f=6cm$

Now, finding "g" by using the formula to calculate the area of the rectangle, we have:

$RectangleArea=ABCD\\\\ABCD=Base*Height\\\\48cm^{2}=base*6cm\\\\base=g=\frac{48cm^{2}}{6cm}=8cm$

Hence, we have that:

$f=6cm\\g=8cm$

Have a nice day!

8 0

3 years ago

IS (3,4) a solution to y<4x-2

Ksivusya [100]

Answer:

lolololololololololololol

Step-by-step explanation:

lololololololololololol

4 0

2 years ago

I have a time limit please hurry!

kumpel [21]

The domain of the relation is 7,13 and the range of the relation is 4,20. I hope this helps.

4 0

3 years ago