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3 years ago

12

Here is a supermarket selles a breakfast cereals three different sizes of box 250g £2.90 350g £4.20 450g £5.31 wich size of the

box is best value give the reason for your answer

1 answer:

yanalaym [24]3 years ago

3 0

Box 250 because it’s the most medium weight

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At the Olympic Games, a runner won the 26.2 mile marathon race in 2 hr 4 min and 1 second. What was his average speed in mph and

Contact [7]

The average speed of the runner is 12.7 mph and 20.4 km/h

Given that the runner ran 26.2 mile in 2hr and 4 minutes, we start of by converting the time from hours and minutes into minutes and finally hours, since hours is what we need. So, we have

2hr = 120mins

+ 4 mins = 124 mins

124 mins ÷ 60 hour/mins = 2.06 hours.

This means that the runner finished the race in 2.06 hours.

If we are to find the average speed in mile per hour, we have

Average speed = distance ran ÷ time taken

Average speed = 26.2 ÷ 2.06

Average speed = 12.7 mph

From the speed in mph, we can directly convert it to km/hr by saying

1 mph = 1.609 km/h

12.7 mph = 12.7 * 1.609 = 20.4 km/hr

for more, check: brainly.com/question/1989219

4 0

2 years ago

I need help :( i don't understand this

maria [59]

Answer: 116.93ft^2

Explanation: find the area of the circle
A= pi•r^2
A=(3.14)•1.5^2= 7.07

Then find the area of the rectangle
A=L•W
A=15.5•8=124

Then do 124-7.07=116.93

You have to subtract the area of the circle from the area of the rectangle because the circle is not shaded in

4 0

3 years ago

The functions f(x) and g(x) are defined below.

erica [24]

-3 is you answer :)
:^

7 0

3 years ago

Help me. And fasttttttttt.

ivann1987 [24]

Answer:

$\sqrt{85}$ = 9.2195 = 9.22

$\sqrt{17}$ = 4.123

Step-by-step explanation:

5 0

3 years ago

Use the algebraic procedure explained in section 8.9 in your book to find the derivative of f(x)=1/x. Use h for the small number

Triss [41]

Answer:

By definition, the derivative of f(x) is

$lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

Let's use the definition for $f(x)=\frac{1}{x}$

$lim_{h\rightarrow 0} \frac{\frac{1}{x+h}-\frac{1}{x}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{x-(x+h)}{x(x+h)}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{(-1)h}{x^2+xh}}{h}=\\lim_{h\rightarrow 0} \frac{(-1)h}{h(x^2+xh)}=\\lim_{h\rightarrow 0} \frac{-1}{x^2+xh)}=\frac{-1}{x^2+x*0}=\frac{-1}{x^2}$

Then, $f'(x)=\frac{-1}{x^2}$

7 0

3 years ago