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8090 [49]
3 years ago
8

What is .0039949x10^12 in scientific notation ?

Physics
1 answer:
strojnjashka [21]3 years ago
6 0
3.9949X10^9 is the answer
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How many significant figures are in 107 moles of sodium
Blizzard [7]

Answer:

3 significant figures

Explanation:

here  zero is counted as one of the significant figures since it lies next to an integer.

hence the number has 3 sfg

8 0
3 years ago
ou are sitting in your car at rest at a traffic light with a bicyclist at rest next to you in the adjoining bicycle lane. As soo
madam [21]

Till the time car is just adjacent to the bicycle we can say

distance moved by cycle = distance moved by car

Time taken by car to accelerate from rest

t = \frac{v_f - v_i}{a}

t = \frac{49 - 0}{7} = 7 s

Time taken by cycle to accelerate

t = \frac{23 - 0}{15} = 1.53 s

now the distance moved by cycle in time "t"

d = \frac{23 + 0}{2}*1.53 + 23(t - 1.53)

distance moved by car in same time

d = \frac{7t + 0}{2}(t)

now make them equal

3.5t^2 = 17.595 - 35.19 + 23t

3.5 t^2 - 23t + 17.595 = 0

t = 5.68 s

so cycle will move ahead of car for t = 5.68 s

8 0
3 years ago
Read 2 more answers
Two masses (5.3kg and 7.5kg) are fastened together with a small amount of explosive. They are loaded into a spring gun that is t
Vsevolod [243]

Answer:

8.2

Explanation:

8 0
3 years ago
Is it illegal to attempt gerrymandering​
IRINA_888 [86]

Explanation:

The US Supreme Court has affirmed in Miller v. Johnson (1995) that racial gerrymandering is a violation of constitutional rights and upheld decisions against redistricting that is purposely devised based on race. However, the Supreme Court has struggled as to when partisan gerrymandering occurs (Vieth v.

8 0
3 years ago
A long thin rod of mass M and length L is situated along the y axis with one end at the origin. A small spherical mass m1 is pla
Yuri [45]

Answer:

= - 5.65\times 10^{-2} J

Explanation:

Given data:

L =2.00 *10^4 m

d = 18*10^4 m

M = 18  *10^6 kg

m_1 = 8*10^6 kg

Gravitational energy is given as

U =- G \frac{m_1 m_2}{r}

mass per unit length is given as

\sigma = \frac{M}{L} = \frac{18 \times 10^6}{2\times 10^4 m} = 900 kg/m

calculating potential energy

dU ==-G\int_{16\times 10^4}^{18\times 10^4} \frac{m_1 *dm}{r}

=-G\int_{16\times 10^4}^{18\times 10^4} \frac{m_1 *\sigma dr}{r}

=-G*m_1*\sigma\int_{16\times 10^4}^{18\times 10^4} \frac{dr}{r}

=-G*m_1*\sigma \left | ln r \right |_{16\times 10^4}^{18\times 10^4}

=-G*m_1*\sigma ln(1.125)

=-6.673 \times 10^{-11}*8*10^6*900*ln(1.125)

= - 5.65\times 10^{-2} J

5 0
3 years ago
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