Gravitational energy is the potential energy associated with gravitational force. If an object falls from one point to another inside a gravitational field, the force of gravity will do positive work on the object and the gravitational potential.
Found this on cha-cha.com
<span>The complete question is:
</span><span>If a liquid is sealed in a container and kept at constant temperature, how does its vapor pressure change
</span>a. it continues to steadily increase
<span>b. it increases at first, then remains constant </span>
<span>c. it increaees at first, then decreases </span>
<span>d. it continues to steadily decrease
</span>
I believe the correct answer is option B. The vapor pressure change would be that it increases at first, then remains constant. <span>More particles escape the liquid and go into the vapor phase at first. But eventually, the number of escaping particles equals the number of particles going back into the liquid.</span>
Resistance
R
of a conducting wire of length
l
and of area of cross section
A
is given by the expression
R
=
ρ
l
A
where
ρ
is resistivity or specific resistance of the material of the conductor.
Inserting given values in the expression in SI units we get
34
=
(
1.7
×
10
−
8
)
l
π
(
0.1
1000
)
2
4
⇒
l
=
34
1.7
×
10
−
8
×
π
4
(
0.1
1000
)
2
⇒
l
=
15.71
m
, rounded to two decimal places.
Answer:
d ) is the answer.
Explanation:
Let M be the mass and R be the radius of each of ball , hoop and disc.
kinetic energy of sphere - 1/2 MV² + 1/2 I ω² ,ω is angular velocity and
V = ωR
kinetic energy of sphere - 1/2 MV² + 1/2 x 2/5 MR² ω²
= 1/2 MV² + 1/5 MR² ω²
MV² ( 1/2 + 1/5 )
= .7 MV²
kinetic energy of Disk - 1/2 MV² + 1/2 I ω² ,ω is angular velocity and
V = ωR
kinetic energy of Disk - 1/2 MV² + 1/2 x 1/2 MR² ω²
= 1/2 MV² + 1/4 MR² ω²
MV² ( 1/2 + 1/4 )
= .75 MV²
kinetic energy of Hoop - 1/2 MV² + 1/2 I ω² ,ω is angular velocity and
V = ωR
kinetic energy of hoop - 1/2 MV² + 1/2 MR² ω²
= 1/2 MV² + 1/2 MR² ω²
MV² ( 1/2 + 1/2 )
= MV²
Kinetic energy is largest in case of hoop and least in case of sphere . So hoop will go up to the highest point and sphere will go to a height which will be least among the three.
The main formula is given by Eb/nucleon = Eb/ mass of nucleid
as for <span>52He, the mass is 5
so by applying Einstein's formula Eb=DmC², Eb=</span><span>binding energy
</span><span>52He-----------> 2 x 11p + 3 x10n is the equation bilan
</span>so Dm=2 mp + (5-2)mn-mnucleus, mp=mass of proton=1.67 10^-27 kg
mn=mass of neutron=<span>1.67 10^-27 kg
</span><span>m nucleus= 5
Dm= 2x</span>1.67 10^-27 kg+ 3x<span>1.67 10^-27 kg-5= - 4.9 J
Eb= </span> - <span>4.9 J x c²= -4.9 x 9 .10^16= - 45 10^16 J
so the answer is Eb /nucleon = Eb/5= -9.10^16 J, but 1eV=1.6 . 10^-19 J
so </span><span>-9.10^16 J/ 1.6 10^-19= -5.625 10^35 eV
the final answer is </span><span>Eb /nucleon </span><span>= -5.625 x10^35 eV</span>