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4 years ago

How does increasing the speed of a motorbike change the amount of energy in its kinetic energy store?

Physics

2 answers:

Kryger [21]4 years ago

8 0

Answer:

If the speed of a motorbike increases, its kinetic energy will also increase.

Explanation:

Kinetic energy is the energy an object has due to its motion, and it is a function of the mass and velocity of the object:

$E_{k}=\frac{m*v^{2}}{2}$

From the expression, it is easy do identify a quadratic relation between kinetic energy and velocity. Therefore, if the speed of a motorbike increases, its kinetic energy will also increase.

For example, if you increase the speed of a motorbike by 10 times, and since mass is a constant value, the kinetic energy will increase by 100 times.

Gnesinka [82]4 years ago

4 0

Answer:

Kinetic energy is energy in motion so therefor if you increase the velocity or in your case speed the kinetic energy also has to increase

Explanation:

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the speed of a tortoise and a hare are 1m/s and 3m/s. the mass of hare is 5kg and the tortoise is 20kg. which has greater moment

Novosadov [1.4K]

Answer: tortoise

Explanation:

Given the following :

Speed of tortoise = 1m/s

Speed of hare = 3m/s

Mass of hare = 5kg

Mass of tortoise = 20kg

Momentum = product of Mass and velocity

Momentum of hare = mass of hare × Velocity of hare

Momentum of hare = 5kg × 3m/s = 15kgm/s

Momentum of tortoise = mass of tortoise × Velocity of tortoise

Momentum of tortoise = 20kg × 1m/s = 20kgm/s

Therefore, tortoise has a greater momentum than hare.

8 0

3 years ago

A school bus moves slower and slower. Using what you have learned about forces, explain why the bus moves slower and slower.

MariettaO [177]

Explanation:

the weight of the people inside the bus

4 0

3 years ago

Un observador se halla a 510m. de una pared. entre el observador y la pared, y a igual distancia de ambos, se realiza un disparo

ch4aika [34]

Answer:

a) t = 0.75 s, b) t = 2.25 s

Explanation:

The speed of sound is constant in a material medium

v = 340 m / s

we can use the relations of uniform motion to find the time

v = x / t

t = x / v

In the exercise, the observer's distance to the wall is indicated d = 510 m, it also indicates that the shot is fired at the midpoint

x = d / 2

a) direct sound the distance from the observer to the screen is

x = 510/2 = 255 m

t = 255/340

t = 0.75 s

b) echo sound.

In this case the sound reaches the wall bounces, the distance is

x = d / 2 + d

x = 3/2 d

x = 3/2 510

x = 765 m

the time is

t = x / v

t = 765/340

t = 2.25 s

5 0

3 years ago

A ski lift carries people along a 220 meter

Amanda [17]

Yes a ski lift carries people among a 220 meter

6 0

4 years ago

At the Indianapolis 500, you can measure the speed of cars just by listening to the difference in pitch of the engine noise betw

allsm [11]

To develop this problem it is necessary to apply the concepts related to the Dopler effect.

The equation is defined by

$f_i = f_0 \frac{c}{c+v}$

Where

$f_h$ = Approaching velocities

$f_i$ = Receding velocities

c = Speed of sound

v = Emitter speed

And

$f_h = f_0 \frac{c}{c+v}$

Therefore using the values given we can find the velocity through,

$\frac{f_h}{f_0}=\frac{c-v}{c+v}$

$v = c(\frac{f_h-f_i}{f_h+f_i})$

Assuming the ratio above, we can use any f_h and f_i with the ratio 2.4 to 1

$v = 353(\frac{2.4-1}{2.4+1})$

$v = 145.35m/s$

Therefore the cars goes to 145.3m/s

7 0

3 years ago