Explanation:
Mass of the astronaut, m₁ = 170 kg
Speed of astronaut, v₁ = 2.25 m/s
mass of space capsule, m₂ = 2600 kg
Let v₂ is the speed of the space capsule. It can be calculated using the conservation of momentum as :
initial momentum = final momentum
Since, initial momentum is zero. So,
So, the change in speed of the space capsule is 0.17 m/s. Hence, this is the required solution.
Answer:
Explanation:
From the question we are told that:
Height of window
Height of window off the ground
Time to fall and drop
Generally the Newton's equation motion is mathematically given by
Where
Generally the Newton's equation motion is mathematically given by
Where
Therefore the ball’s initial speed
Answer:
Explanation:
3.64 x 10⁶ J passes through 6 walls
heat energy passing through 1 wall = 0.606 x 10⁶ J
Surface Area of 1 wall A = .285² = 0.081225 m²
Temperature Difference = T₁ - T₂ = 26.8 + 94.7 = 121.5
Thickness of wall d = 3.75 x 10⁻² m
Rate of heat flow per second R =
=7.01 J per s.
Formula for rate of heat flow
R =
Where K is thermal conductivity.
7.01 =
K = 2.66 X 10⁻² W m⁻¹s⁻¹