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pychu [463]
2 years ago
8

Include information regarding damage to living tissue. Be sure to explain why nuclear energy can cause damage to living tissue.

Include at least one
example to support the information you provide.
Physics
2 answers:
san4es73 [151]2 years ago
6 0

Answer: Radiation is energy. It can come from unstable atoms that undergo radioactive decay, or it can be produced by machines. Radiation travels from its source in the form of energy waves or energized particles. There are different forms of radiation and they have different properties and effects.

Explanation:

Ket [755]2 years ago
6 0
And I oop but it’s tissue

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Energy can be blank from one form to another
Tanya [424]

Answer: "converted"

Energy can be converted from one form to another

Explanation:

The law of conservation of energy states that energy can neither be created nor destroyed but converted from one form to another.

For instance:

- an electric generator convert mechanical energy to electrical energy

- a solar panel system convert solar energy to electrical energy.

- an electric pressing iron convert electrical energy to heat energy

Thus, energy can be converted from one form to another

7 0
3 years ago
Which of the following is an example of an insulator?
charle [14.2K]

Answer:

Hey mate

Answer is glass

7 0
2 years ago
Read 2 more answers
People cut down a forest to bulid a housing development which of the following describes how this action will likely affect the
Ratling [72]

Answer:

It would mean less transpiration and the groundwater would start to make a landslide with no tree root to hold the earth in place

8 0
3 years ago
What are the 4 significant figures of 31,546,000?
ZanzabumX [31]
The 4 significant figures of 31,546,000 are all 8 of the digits.
8 0
3 years ago
Find the potential inside and outside a uniformly charged solid sphere whose radius is R and whose total charge is q. Use infini
amid [387]

Answer:

Recall that the electric field outside  a uniformly charged solid sphere  is exactly the same as if the charge were all at a point in the centre of the  sphere:

E_{outside} =\frac{1}{4\pi(e_{0})}\frac{Q}{r^{2} } r^{'}

lnside the sphere, the electric field also acts like a point charge, but only for the proportion of the charge further inside than the point r:

E_{inside} =\frac{1}{4\pi(e_{0})}\frac{Q}{R^{2} } \frac{r}{R} r^{'}

To find the potential, we integrate the electric field on a path from infinity (where of course, we take the direct path so that we can write the it as a 1 D integral):

V(r>R)=\int\limits^r_\infty {\frac{1}{4\pi(e_{0)} }\frac{Q}{r^2}  } \, dr=\frac{q}{4\pi(e_{0)} } \frac{1}{r} \\V(r

=\frac{q}{4\pi e_{0} } [\frac{1}{R} -\frac{r^{2}-R^{2}  }{2R^{3} } ]

∴NOTE: Graph is attached

8 0
3 years ago
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