Simplify quantity x squared plus 6 x plus 8 end quantity over quantity x plus 2

Mathematics

1 answer:

Novosadov [1.4K]2 years ago

5 0

Simplifying quantity x squared plus 6 x plus 8 end quantity over quantity x plus 2 we get x+4

Option d is correct.

Step-by-step explanation:

We need to simplify quantity x squared plus 6 x plus 8 end quantity over quantity x plus 2.

Writing in mathematical form:

$\frac{x^2+6x+8}{x+2}$

Solving:

Factorizing the numerator:

$\frac{x^2+6x+8}{x+2}\\=\frac{x^2+4x+2x+8}{x+2}\\=\frac{x(x+4)+2(x+4)}{x+2}\\=\frac{(x+2)(x+4)}{x+2}\\Cancelling\,\,x+2\,\,forom\,\,numerator\,\,and\,\,denominator:\\=x+4$

So simplifying quantity x squared plus 6 x plus 8 end quantity over quantity x plus 2 we get x+4

Option d is correct.

Keywords: Simplifying Expressions

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