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3 years ago

5

Find the midpoint between each pair of points. (-1, -5) and (-5, 9)

1 answer:

777dan777 [17]3 years ago

3 0

Answer:

$(-3,2 )$

Step-by-step explanation:

Midpoint Formula: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )$

Simply plug in your coordinates into the midpoint formula to find midpoint:

$(\frac{-1-5}{2},\frac{-5+9}{2} )$

$(\frac{-6}{2},\frac{4}{2} )$

$(-3,2 )$

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WILL GIVE BRAINLEST ANSWER IF ANSWERED IN THE NEXT 24 HRS Express the complex number in trigonometric form. -5i

trasher [3.6K]

Answer:

$z=5\left(\cos \left(\dfrac{3\pi}{2}\right)+i\sin \left(\dfrac{3\pi}{2}\right)\right)$

Step-by-step explanation:

If a complex number is z=a+ib, then the trigonometric form of complex number is

$z=r(\cos \theta +i\sin \theta)$

where, $r=\sqrt{a^2+b^2}$ and $\tan \theta=\dfrac{b}{a}$ , $\theta$ is called the argument of z, $0\leq \theta\leq 2\pi$ .

The given complex number is -5i.

It can be rewritten as

$z=0-5i$

Here, a=0 and b=-5. $\theta$ lies in 4th quadrant.

$r=\sqrt{0^2+(-5)^2}=5$

$\tan \theta=\dfrac{-5}{0}$

$\tan \theta=\infty$

$\theta=2\pi -\dfrac{\pi}{2}$ $[\because \text{In 4th quadrant }\theta=2\pi-\theta]$

$\theta=\dfrac{3\pi}{2}$

So, the trigonometric form is

$z=5\left(\cos \left(\dfrac{3\pi}{2}\right)+i\sin \left(\dfrac{3\pi}{2}\right)\right)$

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3 years ago

Read 2 more answers

Firewood is often sold by the cord. A cord of wood is a bundle measuring 4 feet by 4 feet by 8 feet. What's the volume of a cord

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To find the volume of the following Firewood, we would do this:

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2 years ago

Which expressions are equivalent to (2^2-9) (x + 3)?

mestny [16]

Answer:

$(x^2-3^2)(x+3)$

$(x-3)(x+3)(x+3)$

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Step-by-step explanation:

Given

$(x^2-9)(x+3)$

Required

Select 3 equivalent expressions

$(x^2-9)(x+3)$

Express 9 as 3^2

$(x^2-3^2)(x+3)$ --- This is one equivalent expression

Take $x^2 - 3^2$ as difference of two squares

$(x-3)(x+3)(x+3)$ -- This is another equivalent expression:

Solving further:

$(x-3)(x+3)(x+3)$ becomes

$(x-3)(x+3)^2$ -- This is another equivalent expression:

Hence, the equivalent expressions are:

$(x^2-3^2)(x+3)$

$(x-3)(x+3)(x+3)$

$(x-3)(x+3)^2$

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Answer:

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