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Gnom [1K]
3 years ago
5

The purple Arrow shows speed and direction of the ball. This arrow is called ______.

Physics
2 answers:
tia_tia [17]3 years ago
7 0

The arrow is called Vector.

serg [7]3 years ago
5 0

Correct Answer :

D- A Vector

quantity that has both magnitude and direction. It is typically represented by an arrow whose direction is the same as that of the quantity



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Nutritionists call the calories found in junk food _____ calories due to lack of quality nutrients.
Nikolay [14]

Answer:

empty

Explanation:

Nutritionists call the calories found in junk food empty calories due to lack of quality nutrients.

Empty calories refer to calories derived from foods containing no quality nutrients. These foods are mainly junk food; food that contains high calories derived from fat or sugars and with little or no proteins, fiber, dietary minerals or vitamins. These foods are not healthy as their prolonged consumption can lead to an increased risk of obesity.

6 0
4 years ago
Three people bought copper items, and they each relied on different properties of copper. Bernie bought a set of dishes that inc
Luden [163]

The answer is A.

Copper is conductive hence Bernie could use the copper bowl to easily warm his food.

Copper is ductile hence Nicholas can easily bend his copper wire gauge

Copper is malleable hence can be easily shaped into a form hence used to make a bracelet for Matt’s mother.  


3 0
3 years ago
Read 2 more answers
If the ball leaves the projectile launcher at a speed of 2.2 m/s at an angle of 30ᴼ, and the projectile launcher is on a table a
IgorC [24]

Answer: 1.12 m

Explanation:

This situation is related to parabolic motion, hence we can use the following equations:

y=y_{o}+V_{o}sin \theta t-\frac{g}{2}t^{2} (1)

x=V_{o} cos \theta t (2)

Where:

y=0 m is the ball final height (when it hits the ground)

y_{o}=1.1 m is the ball initial height

V_{o}=2.2 m/s is the initial velocity

\theta=30\° is the angle at which the ball was launched

t is the time

g=9.8 m/s^{2} is the acceleration due gravity

x is the horizontal distance the ball travels

Rewriting (1) with the given values:

0 m=1.1 m+(2.2 m/s)(cos 30\°)t-\frac{9.8 m/s^{2}}{2}t^{2} (3)

Multiplying all the eqquation by -1 and rearranging:

4.9 m/s^{2} t^{2}-1.1 m/s t-1.1 m=0 (4)

So, since we have a quadratic equation here (in the form of0=at^{2}+bt+c,  we will use the quadratic formula to find  t:  

t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}   (5)

Where a=4.9, b=-1.1, c=-1.1  

Substituting the known values and choosing the positive result of the equation, we have:  

t=\frac{-(-1.1)\pm\sqrt{(-1.1)^{2}-4(4.9)(-1.1)}}{2(4.9)}  

t=0.59 s (6)

Now, substituting (6) in (2):

x=(2.2 m/s)(cos 30\°)(0.59 s) (7)

x=1.12 m (8) This is the horizontal distance at which the ball hits the ground.

3 0
4 years ago
Question 5 help please
IrinaVladis [17]

Answer:

It is another machine that helps the main machine. Hope that helps!

5 0
3 years ago
A 10-cm-long archerfish begins such a leap with its body vertical in the water, using its fins and undulating its body to propel
siniylev [52]

Answer:

Explanation:

Velocity will be equal to the area under the curve of the acceleration-time plot.

v = ½(45)(0.075) = 1.6875

v = 1.7 m/s

h = (0² - 1.6875²) / (2(-9.8)) =  0.145288...

h = 15 cm

3 0
3 years ago
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