All categories

3 years ago

Please help I will mark Brainly

Mathematics

1 answer:

Sloan [31]3 years ago

7 0

Answer:

The answer to number 1 is 10. The answer to number 2 is 4-6, inclusive.

You might be interested in

| 2p -1 | =45, what are the values of p?

Alex73 [517]

Answer:

p = 23 and p = -22

Step-by-step explanation:

| 2p -1 | =45

Absolute value equations have 2 solutions, one positive value and one negative

2p-1 = 45 and 2p-1 = -45

Add 1 to all sides

2p-1+1 = 45+1 and 2p-1+1 = -45+1

2p = 46 2p = -44

Divide by 2

2p/2 = 46/2 and 2p/2 = -44/2

p = 23 and p = -22

5 0

3 years ago

Read 2 more answers

Determine the point of intersection of right bisectors in a triangle ∆ with vertices A (-3, 5), B (1, 1) and (−7, −3). Find the

iris [78.8K]

Answer:

Point of intersection (-11/3 , 1/3)

All distances from the vertices are $\frac{10\sqrt{2} }{3}$

Step-by-step explanation:

The vertices of the triangle is A(-3,5) , B (1,1) and C (-7,-3)

We need to find the perpendicular bisector of the triangle first

let's take one side connecting A and B

mid point of A and B = (-1,3)

Slope of the line joining A and B = -1

slope of perpendicular to line joining A and B = 1

equation of line passing through (-1,3) with slope 1

y - 3 = 1(x-(-1))

y -3 = x+1

x-y = -4 ............(1)

similarly

mid point joining B and C = (-3,-1)

slope perpendicular to line joining B and C = -2

Equation of perpendicular bisector of line joining B and C =

y +1 = -2(x +3 )

y+1 = -2x -6

2x+y = -7 ..........(2)

On solving 1 and 2

x= -11/3 , y= 1/3

Distances

From A = $\frac{10\sqrt{2} }{3}$

From B = $\frac{10\sqrt{2} }{3}$

From C = $\frac{10\sqrt{2} }{3}$

7 0

3 years ago

Need helpp fastt plss will give brainliest to who is correct plss helpp

katen-ka-za [31]

Answer:

352

Step-by-step explanation:

(216-128)*(4)

(88)*(4)

352

4 0

3 years ago

Simplify:<br><br>7j-6k-5j+4k<br><br>also what is 30% of 520

alukav5142 [94]

The first one simplified is 2j-2k 30% of 520 is 156

7 0

4 years ago

Find the area bounded by the curve y = x 1/2 + 2, the x-axis, and the lines x = 1 and x = 4 A. 16 B. 10 2/3 C. 7 1/2 D. 28 1/2

jeka94

To find the area of the curve subject to these constraints, we must take the integral of y = x ^ (1/2) + 2 from x=1 to x=4
Take the antiderivative: Remember that this what the original function would be if our derivative was x^(1/2) + 2
antiderivative (x ^(1/2) + 2) = (2/3) x^(3/2) + 2x
* To check that this is correct, take the derivative of our anti-derivative and make sure it equals x^(1/2) + 2

To find integral from 1 to 4:
Find anti-derivative at x=4, and subtract from the anti-derivative at x=1
2/3 * 4 ^ (3/2) + 2(4) - (2/3) *1 - 2*1
2/3 (8) + 8 - 2/3 - 2 Collect like terms
2/3 (7) + 6 Express 6 in terms of 2/3
2/3 (7) + 2/3 (9)
2/3 (16) = 32/3 = 10 2/3 Answer is B

6 0

4 years ago