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Murljashka [212]
3 years ago
8

How do you solve this

Mathematics
1 answer:
Dimas [21]3 years ago
3 0
80%  because I did the math


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How do you find 33% of $84?
My name is Ann [436]
33% = 0.33

'of' indicates multiplication

0.33 * 84 = 27.72

So $27.72
8 0
4 years ago
Read 2 more answers
Jack purchases 12 gallons of gas on Monday. He uses 2/3
motikmotik

Answer:

Gallons of gas use for work and errands is <u>10</u>.

Step-by-step explanation:

Given:

Jack purchases 12 gallons of gas on Monday. He uses 2/3  of the amount purchased commuting to and from work during the week and an additional 2 gallons running errands.

So, to find the gallons of gas Jack use for work and errands:

Now, to get the amount of gas used to and from work during the week

=\frac{2}{3}of12

=\frac{2}{3}\times 12

=\frac{24}{3}=8\ gallons.

Additional 2 gallons of gas running errands.

Now,<em> total gallons of gas use for work and errands = 8 gallons + 2 gallons</em>

<em>                                                                                      = 10 gallons.</em>

Therefore, gallons of gas use for work and errands is 10.

8 0
3 years ago
Read 2 more answers
Very small numbers are often written in exponential form using scientific notation to make them easier to multiply or divide. Ex
Tems11 [23]
The laws of exponents that are often used in calculating values written in scientific notation are

a^m*a^n = a^{m+n}, and
\frac{a^m}{a^n}= a^{m-n}

for example;
10^6*10^{-7}=10^{(6+-7)}=10^{-1}
\frac{10^{-8}}{10^{-9}}=10^{(-8--9)}=10^1
6 0
3 years ago
How do I do this one
ira [324]

think of x as one so you would graph y axis as 4 and x axis as 1

8 0
3 years ago
Sid intended to type a seven-digit number, but the two 3's he meant to type did not appear. What appeared instead was the five-d
Papessa [141]

Answer:

21 ways

Step-by-step explanation:

number = 7 digit

5 digit no = 52115

to find out

How many different seven-digit numbers

solution

first we need to place the two missing 3s in the number 52115

we consider here two cases

case 1  the two 3's appear separated (like 532135 or 3521135)  

case 2 the two 3's appear together (like 5332115 or 5211533)  

Case 1 we can see  that number type as _5_2_1_1_5_  

place 3's placeholders show potential locations

( type a ) for  3's  separated we will select 2 of  6 place and place 3 in every location so we do this 6C2  = (15) ways  

and (type b): again use same step as  _5_2_1_1_5_  

here 3s together for criterion and we will select 1 of the 6 place and place both 3s here and there are 6 ways.  

so that here will be 15+6=21 ways

If 3 and 3 are separate so 6C2 = 15  ways

If 3 and 3 are together so there = 6  ways

= 15 + 6 = 21 ways

8 0
3 years ago
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