Plane #1 speed: x mph
Plane #2 speed: (x+30) mph
time = time becomes
170 mi 185 mi
---------- = --------------
x x+30
Solving for x, the speed of the slower plane, we get
170x + 5100 = 185 x
5100
Then 15x = 5100, and x = ---------- (mi/hr) = 340 mph
15
The slower plane flies at 340 mph, and the faster one at 370 mph.
Answer: (x-3)/3
Step-by-step explanation:
You have to multiply the fraction.
Answer: 60 mph.
(486+316+638)/24
The distances given by the table. The time driven is 24 (given by the problem). So the average speed is simply the total distance divided by the time driven.
Step-by-step explanation:
Answer:
13x-9
Step-by-step explanation:
9×(x - 1)
9x - 9 +4x
collect like terms, 9x+4x=13x
Bearing is a topic that can be used to <u>locate</u> the <em>position</em> of an object at a given time. Therefore, the blimp is <em>80 m</em> far away from its <u>starting</u> point. And in the<em> North-East </em>direction.
The <u>speed</u> of an object relates the <em>distance</em> it covers to the <u>time taken</u> to cover the said distance.
i.e speed = 
⇒ distance = speed x time taken
In the given question, the <u>initial</u> distance covered can be determined as;
distance = 40 mph x 3 h
= 120 m
The<u> final </u>distance covered can be determined as;
distance = 40 mph x 1 h
= 40 m
Let the <u>distance</u> from its <em>starting</em> point to its <em>fina</em>l location be represented by x.
Thus applying the<em> Cosine rule</em>, we have:
=
+
- 2abCos C
=
+
- 2(120 x 40) Cos 90
= 14400 + 1600 - 9600
= 16000 - 9600
= 6400
x = 
= 80
x = 80 m
Therefore, the <u>distance</u> of the blimp from its <em>starting</em> point to its <em>final</em> destination is <u>80 m</u>.
For more clarifications on bearings, visit: brainly.com/question/22979472
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