What two numbers multiply to give 36 but add up to -13

Mathematics

2 answers:

riadik2000 [5.3K]2 years ago

7 0

Answer:

-4 and -9

Step-by-step explanation:

ra1l [238]2 years ago

5 0

The numbers -9 and -4
Hope this helped :)

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Someone please help! Thxx

tangare [24]

Answer:

E, needs more info to be determined

Step-by-step explanation:

We know that Kai takes 30 minutes round-trip to get to his school.

One way is uphill and the other is downhill.

He travels twice as fast downhill than uphill.

This means that uphill accounts for 20 minutes of the round-trip and downhill accounts for 10 minutes of his trip.

However, even with this information, we do not know how far his school is.

In order to figure out how far away his school is, we would need more information about the speed at which Kai is traveling.

Simply knowing that he travels twice as fast downhill is not enough.

This question could only be solved by knowing how many miles Kai travels uphill or downhill in a given time.

3 0

2 years ago

Write the equation in slope-intercept form.

professor190 [17]

Y - 11 = 3(x + 4)....distribute thru the parenthesis
y - 11 = 3x + 12....add 11 to both sides
y = 3x + 12 + 11...simplify
y = 3x + 23 <==

4 0

2 years ago

Can someone help please

myrzilka [38]

<h3>Answer: 15x^(7/3) - 8x^(7/4) + x + 9000</h3>

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Explanation:

If you know the cost function C(x), to find the marginal cost, we apply the derivative.

Marginal cost = derivative of cost function

Marginal cost = C ' (x)

Since we're given the marginal cost, we'll apply the antiderivative (aka integral) to figure out what C(x) is. This reverses the process described above.

$\text{Cost} = \text{antiderivative of marginal cost}\\\\\displaystyle C(x) = \int \left(35x^{4/3} - 14x^{3/4} + 1\right)dx\\\\$

$C(x) = \frac{1}{1+4/3}*35x^{4/3+1} - \frac{1}{1+3/4}*14x^{3/4+1} + x + D\\\\C(x) = \frac{1}{7/3}*35x^{7/3} - \frac{1}{7/4}*14x^{7/4} + x + D\\\\C(x) = \frac{3}{7}*35x^{7/3} - \frac{4}{7}*14x^{7/4} + x + D\\\\C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\$

D represents a fixed constant. I would have used C as the constant of integration, but it's already taken by the cost function C(x).

To determine the value of D, we plug in x = 0 and C(x) = 9000. This is because we're told the fixed costs are $9000. This means that when x = 0 units are made, you still have $9000 in costs to pay. This is the initial value. You'll find that all of this leads to D = 9000 because everything else zeros out.

Therefore, we go from this

$C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\$