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Dahasolnce [82]

3 years ago

11

-5x+13y=-7 5x+4y=24 system of equations

1 answer:

Lostsunrise [7]3 years ago

4 0

The answer is (4,1)
Add both equations you get
17y = 17
y = 1
Substitute y = 1 into the second equation
5x+4(1) = 24
5x = 20
x = 4

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An experiment consists of choosing objects without regards to order. Determine the size of the sample space when you choose the

sdas [7]

Answer:

a

$n= 75, 582$

b

$n= 2300$

c

$n = 253$

Step-by-step explanation:

Generally the size of the sample sample space is mathematically represented as

$n = \left N } \atop {}} \right. C_r$

Where N is the total number of objects available and r is the number of objects to be selected

So for a, where N = 19 and r = 8

$n = \left 19 } \atop {}} \right. C_8 = \frac{19 !}{(19 - 8 )! 8!}$

$= \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}$

$n= 75, 582$

For b Where N = 25 and r = 3

$n = \left 25 } \atop {}} \right. C_3 = \frac{25 !}{(19 - 3 )! 3!}$

$= \frac{25 *24 *23 *22 ! }{22 ! \ 3!}$

$n= 2300$

For c Where N = 23 and r = 2

$n = \left 23 } \atop {}} \right. C_2 = \frac{23 !}{(23 - 2 )! 2!}$

$= \frac{23 *22 *21! }{21 ! \ 3!}$

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3 years ago

Maria had planned to walk 10 1/8 miles on wednesday, if she walked 7 2/8 miles in the morning how far would she need to walk in

Ugo [173]

Answer:

Distance Maria had to walk in the afternoon is $2\frac{7}{8}$

Step-by-step explanation:

Lets take that Maria walked $x$ miles in the afternoon.

Distance walked in the morning + distance walked in the afternoon = $10\frac{1}{8}$

⇒ $7\frac{2}{8} +x=10\frac{1}{8}$

$\frac{58}{8} +\frac{8x}{8} =\frac{81}{8}$

$\frac{58+8x}{8} =\frac{81}{8}$

$58+8x=81$

$8x=81-58\\$

$8x=23$

$x=\frac{23}{8}$

$x=2\frac{7}{8}$

7 0

3 years ago