Answer:
0.52763 is the probability that the time between the next two calls will be 54 seconds or less.
0.19285 is the probability that the time between the next two calls will be greater than 118.5 seconds.
Step-by-step explanation:
We are given the following information in the question:
The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.2 minutes.
The distribution function can be written as:
The probability for exponential distribution is given as:
a) P( time between the next two calls will be 54 seconds or less)
0.52763 is the probability that the time between the next two calls will be 54 seconds or less.
b) P(time between the next two calls will be greater than 118.5 seconds)
0.19285 is the probability that the time between the next two calls will be greater than 118.5 seconds.
The expanded form would be: 9 x 2 x 100
option c is the correct cofficient of 3
Answer:
A. Miguel has the greatest spread.
The range of the two persons can be determined by:
Adam's range = 106 -91
= 15
Miguel's range = 105 -86
= 19
B. Considering the middle 50% of the training time, the person with the least spread is Adam.
Adam - 103 105 104 106 100
Miguel - 88 86 89 93 105
Adam's 50% range = 106 - 100
= 6
Miguel's 50% range = 105 - 86
= 19
Adam has the least spread
C. Miguel is inconsistent with the time set for training compared to that of Adam.
The answers to parts 2a and 2b show that there is a wide variation in the time that Miguel spend during training, but a minimum variation in the time spent by Adam during training.
Answer:
The 3 statements that are correct are:
<em><u>1. "Plan A offers fewer movies than Plan B for monthly costs greater than 20$"</u></em>
<em><u>2. "The two plans cost the same for 10 movies per month"</u></em>
<em><u>3. "The two plans offer the same number of movies for 20$ a month."</u></em>
