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alexira [117]
3 years ago
12

Consider three equal sources m in a triangular configuration: one at (a/2, 0), one at (−a/2, 0) and one at (0, a). Plot the stre

amlines for this flow use Matlab. Are there any stagnation points?
Mathematics
1 answer:
belka [17]3 years ago
4 0

Answer:its the third one i took the test

Step-by-step explanation:

You might be interested in
What is 14/74 in simplest form
charle [14.2K]
14/74 in the simplest form is 7/37
5 0
3 years ago
A carpenter needs to cut a 5 foot, 8 inch piece of wood from an 8-foot board to make a repair to a door. How many inches of wood
erastovalidia [21]

Answer:

Step-by-step explanation:

1 foot = 12 inches

length of board in inches = 8 ft × (12 in)/ft = 96 in

length of cut in inches = 5 ft + 8 in = 5 ft × (12 in)/ft + 8 in = 60 in + 8 in =  68 in.

96 - 68 = 28 inches left

3 0
2 years ago
Please help if you answer correctly I will give brainliest thank you!!!!!!!!
ivolga24 [154]

Answer:

The Answer is C

Step-by-step explanation:

3x-4y=5

2x+4y=-3

This equation is the answer to this problem because just by looking at it, you can immediately cancel out the y value and solve for x.

The other equations are wrong because their is extra work needed to eliminate the values.

4 0
3 years ago
A jet travels from chicago to kansas city at a speed of 440 knots. If it takes a plane 3 hr longer to fly from kansas city to ch
steposvetlana [31]

d = distance between the two cities

v₁ = average speed while going from chicago to kansas city = 440 knots

t₁ = time taken to travel distance going from chicago to kansas city

time taken to travel distance going from chicago to kansas city is given as

t₁ = d/v₁

t₁ = d/440                                        eq-1


v₂ = average speed while going from kansas city to chicago = 110 knots

t₂ = time taken to travel distance going from kansas city to chicago

time taken to travel distance going from kansas city to chicago is given as

t₂ = d/v₂

t₂ = d/110                                                     eq-2


Given that :

t₂ = t₁ + 3

using eq-1  and eq-2

(d/110) = (d/440) + 3

d = 440

7 0
3 years ago
a motorist left home at 10 a.m. to travel to a cityof a distance of 260 km he reckoned hecould average 80km/ h at what time woul
kap26 [50]

Answer:

He would get there at 1:15 (I did this in my head, may be wrong)

Step by step solution:

We know the motorist left home at 10. We can divide the 260/80 and we get 3 hrs, we still have 20 km left over, keep on dividing and you get 1:15 p.m.

6 0
2 years ago
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