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tangare [24]
3 years ago
5

Why are there 2 chloride ions for every 1 calcium in calcium chloride

Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
5 0

Answer:

See explanation

Explanation:

Calcium is divalent. This means that it donates two electrons during ionic bond formation. Since chlorine atom can only accept one electron during ionic bond formation, two chlorine atoms must accept the two electrons donated by calcium.

For this purpose, each time CaCl2 is formed, there must be two chlorine atoms for each calcium atom.

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Ammonia is produced by the following reaction. 3H2(g) N2(g) Right arrow. 2NH3(g) When 7. 00 g of hydrogen react with 70. 0 g of
harkovskaia [24]

In the ammonia production process given by the reaction 3H₂(g) + N₂(g) → 2NH₃(g), when 7.00 g of hydrogen react with 70.0 g of nitrogen, hydrogen is considered the limiting reactant because <u>7.5 moles of hydrogen would be needed to consume the available nitrogen</u> (option 1).

The reaction is the following:

3H₂(g) + N₂(g) → 2NH₃(g)   (1)

To know why hydrogen is considered the limiting reactant, we need to calculate the number of moles of nitrogen and hydrogen with the following equation:

n = \frac{m}{M}

Where:    

m: is the mass

M: is the molar mass

  • For <em>hydrogen </em>we have:

n_{H_{2}} = \frac{m}{M} = \frac{7.00 g}{2.016 g/mol} = 3.47 \:moles

  • And for <em>nitrogen</em>:

n_{N_{2}} = \frac{m}{M} = \frac{70.0 g}{28.013 g/mol} = 2.50 \:moles

We can see in reaction (1) that <u>3 moles of hydrogen</u> react with <u>1 mol of nitrogen</u>, so the number of hydrogen moles needed to react nitrogen is:

n_{H_{2}} = \frac{3\:moles\:H_{2}}{1\:moles\:N_{2}}*n_{N_{2}} = \frac{3\:moles\:H_{2}}{1\:moles\:N_{2}}*2.50 \:moles = 7.50 \:moles

Since we have <u>3.47 moles of hydrogen</u> and we need <u>7.50 moles</u> to react with all the mass of nitrogen, the <em>limiting reactant</em> is <em>hydrogen</em>.

We can find the number of ammonia moles produced with the limiting reactant (hydrogen) konwing that <u>3 moles of hydrogen</u> produces <u>2 moles of ammonia</u>, so:

n_{NH_{3}} = \frac{2\:moles\:NH_{3}}{3\:moles\:H_{2}}*n_{H_{2}} = \frac{2\:moles\:NH_{3}}{3\:moles\:H_{2}}*3.47 \:moles = 2.31 \:moles

Hence, hydrogen would produce <u>2.31 moles of ammonia</u>.

Therefore, hydrogen is the limiting reactant because <u>7.5 moles of hydrogen would be needed to consume the available nitrogen</u> (option 1).

Find more about limiting reactants here:

brainly.com/question/2948214?referrer=searchResults

   

I hope it helps you!                        

6 0
3 years ago
How can I tell how many electrons in each energy level? When my question states "third sublevel" does this mean sublevel P?
nikitadnepr [17]
Sorry for the delay! My internet is a bit bad.
P is the third sublevel. Each sublevel (the angular momentum quantum number), has its own number:
<span>s = 1, p =3, d = 5, f = 7</span>
The number of electrons for each is:
s-2
p-6
d-10
f-14
It's easier to just memorize these numbers, but the equation for determining the sublevel number is 2n (n = the principal quantum number). The principal quantum number is based on the period the element is in.
6 0
3 years ago
In a metallic bond, electrons
kobusy [5.1K]
The answer would be c
8 0
3 years ago
Organic compounds are a source of _______.​
jek_recluse [69]

Answer:

<h2>Petroleum and coaltar are the main sources of organic compounds. <u>(edit: Protein is most likely correct because I did some further research and I am mistaken I believe the other answer is right because it is also found to be a source of energy aka protein)</u></h2>

Explanation:

4 0
3 years ago
g What is the molarity of hydrochloric acid if 40.95 mL of HCl is required to neutralize 0.550 g of sodium oxalate, Na2C2O4
kykrilka [37]

Answer:

0.0002 M

Explanation:

<em>The molarity of the HCl required would be 0.0002 M.</em>

First, let us consider the balanced equation of the reaction:

Na_2C_2O_4 + 2HCl = 2NaCl + H_2 + 2CO_2

<em>Stoichiometrically, 1 mole of </em>Na_2C_2O_4<em> reacts with 2 moles of </em>HCl<em> for a complete neutralization reaction.</em>

Recall that: mole = \frac{mass}{molar mass}

Mole of 0.550 g sodium oxalate = 0.550/134 = 0.0041 mole

<em>If 1 mole </em>Na_2C_2O_4<em> requires 2 moles HCl, then 0.0041 mole will require</em>:

    0.0041 x 2 = 0.0082 mole HCl

Volume of the HCl = 40.95 L

Molarity = mole/volume

Hence, molarity of the HCl = 0.0082/40.95 = 0.0002 M

7 0
3 years ago
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