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VladimirAG [237]
2 years ago
7

If the temperature is below zero, what will the precipitation most likely be?

Chemistry
1 answer:
Leviafan [203]2 years ago
7 0

Answer: C Snow

Explanation:

Because the temperature is low and it is below freezing temperature. Sorry if I am wrong.

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What is the relative humidity of the air when the dry-bulb temperature is 4°C and the dewpoint is -4°C?
boyakko [2]

Answer:56%

Explanation:

In the dewpoint chart when you line it up it ends up at 56%

3 0
3 years ago
Points)<br> Determine the molar mass of NaCl (the solute) in a 0.1M aqueous solution of NaCl
nalin [4]

Answer:

  58.443 g/mol

Explanation:

The molar mass of NaCl is the sum of the molar masses of the individual atoms:

  Na: 22.989770 g/mol

  Cl: 35.453 g/mol

The total molar mass is ...

  NaCl: 58.443 g/mol

__

The molar mass does not depend on whether the material is in solution or in any other form.

4 0
3 years ago
6.0 g of copper was heated from 20 degree c to 90 degree c . How much energy was used to heat cu?
Darina [25.2K]
Copper heat capacity would be <span>0.385J/C*gram which means it needs 0.385 Joule of energy to increase 1 gram of copper temperature by 1 Celcius. The calculation would be:
energy= heat capacity *mass * temperature difference
energy= </span>0.385J/C*gram * 6g * (90-20)
<span>energy= 161.7J
 </span>
4 0
3 years ago
The technology in the picture produces which energy conversion
BARSIC [14]
D) kinetinc to electric
7 0
3 years ago
Read 2 more answers
What is the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from an energy level with n =
Lady bird [3.3K]

Answer:

4.86\times10^{-7}\ \text{m}

Explanation:

R = Rydberg constant = 1.09677583\times 10^7\ \text{m}^{-1}

n_1 = Principal quantum number of an energy level = 2

n_2 = Principal quantum number of an energy level for the atomic electron transition = 4

Wavelength is given by the Rydberg formula

\lambda^{-1}=R\left(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2}\right)\\\Rightarrow \lambda^{-1}=1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\\\Rightarrow \lambda=\left(1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\right)^{-1}\\\Rightarrow \lambda=4.86\times10^{-7}\ \text{m}

The wavelength of the light emitted is 4.86\times10^{-7}\ \text{m}.

6 0
2 years ago
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