Answer:
The primary role of the carbonic-acid-bicarbonate buffer system is to neutralize the hydronium ions forming carbonic acid and water when any acidic substance enter the bloodstream.
Explanation:
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Answer:
11.3 g.
Explanation:
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In this case, since the combustion of butane is:

Thus, since there is a 1:5 mole ratio between butane and water, we obtain the following mass of water:

Therefore, the resulting mass of water is:

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you add the masses of the reactants, because of conservation of mass. if there are two or more products they will ask you to find the mass of only one product or the sum of the mass of all products
<h3>Answer:</h3>
36 moles of Hydrogen
<h3>Solution:</h3>
The molecular formula of Glucose is,
C₆H₁₂O₆
As clear from molecular formula, each mole of Glucose contains 12 moles of Hydrogen atoms.
Therefore,
1 mole of C₆H₁₂O₆ contains = 12 moles of Hydrogen
So,
3.0 moles of C₆H₁₂O₆ will contain = X moles of Hydrogen
Solving for X,
X = (3.0 mol × 12 mol) ÷ 1 mol
X = 36 moles of Hydrogen