<span>You are given a rectangular picture measuring 8 inches by 7 inches. Also, Alistair wants this to be framed and that the total area is 34 square inches. The width of the frame is x inches. To solve the dimension of the frame with value of x we have:
We have to assume that x here will be equal to all sides of the frame and so, using the area of the rectangle, we can model the equation like this:
A = LW (where A is the area, L is the length and W is the width)
36 = (8 - x)(7 - x)
36 = 56 - 8x - 7x + x</span>²
<span>x</span>² - 15x +20 = 0 → model of our equation and in quadratic form
x² - 15x + 20 = 0
using a calculator, x = 1.48 inches
<span>
3.Use the equation you created in part A to find the width of the picture frame</span>
Answer:
Replace all occurrences of y with 2x−1 in each equation.
0=0
y=2x−1
Remove any equations from the system that are always true.
y=2x−1
Step-by-step explanation:
Answer:
-I haven't done this, but I have copied and pasted from another question and answer from the user syed514:
Graphing is one way to do the problem.But sometimes, graphing it is hard to do.So here’s an algebraic method.
If M(m1, m2) is the midpoint of two points A(x1, y1) and B(x2, y2),then m1 = (x1 + x2)/2 and m2 = (y1 + y2)/2.In other words, the x-coordinate of the midpointis the average of the x-coordinates of the two points,and the y-coordinate of the midpointis the average of the y-coordinates of the two points.
Let B have coordinates (x2, y2) in our problem.Then we have that 6 = (2 + x2)/2 and 8 = (3 + y2)/2.
Solving for the coordinates gives x2 = 10, y2 = 13
