Recall that
d/dx sech(x) = - sech(x) tanh(x)
d/dx tan⁻¹(x) = 1/(1 + x²)
Then by the chain rule,
dy/dx = - sech(x) tanh(x) / (1 + x²)
Yes all equilateral triangles are congruent. You can prove congruence with two congruent angles and all equilateral triangles will have 60º angles. Which is enough to prove similarity
Answer:
A y = x + 1
Step-by-step explanation:
The line starts at 1 on the y-axis so the u intercept will be 1
