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koban [17]
3 years ago
12

2/3p+3. p=3/5 What is the Answer to what

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
3 0

Step-by-step explanation:

2/3p+3

where p=3/5

substitute p into 2/3p + 3

2/3(3/5) + 3

2/(9/5) + 3

10/9 + 3

10+3)/9

13/9

1 4/9

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5 3/2 x 3 6/7 you have 10 point to do the answer
pogonyaev

Step-by-step explanation:

Conversion a mixed number 5 3/2

to an improper fraction: 5 3/2 = 5 3/2

= 5 · 2 + 3/2

= 10 + 3/2

= 13/2

To find a new numerator:

a) Multiply the whole number 5 by the denominator 2. Whole number 5 equally 5 * 2/2

= 10/2

b) Add the answer from previous step 10 to the numerator 3. New numerator is 10 + 3 = 13

c) Write a previous answer (new numerator 13) over the denominator 2.

Five and three halfs is thirteen halfs

Conversion a mixed number 3 6/7

to an improper fraction: 3 6/7 = 3 6/7

improper fraction: 3 6/7 = 3 6/7

3 · 7 + 6/7 = 21 + 6/7 =27/7

To find a new numerator:

a) Multiply the whole number 3 by the denominator 7. Whole number 3 equally 3 * 7/7

= 21/7

b) Add the answer from previous step 21 to the numerator 6. New numerator is 21 + 6 = 27

c) Write a previous answer (new numerator 27) over the denominator 7.

Three and six sevenths is twenty-seven sevenths

Multiple:

13/2 * 27/7 = 13/2 · 27/7 = 351/14

3 0
2 years ago
A block of cheese has a volume of 178 cm3 and a mass of 120 g.
Anna35 [415]

Answer:

375

Step-by-step explanation:

7 0
3 years ago
Please help solve this question with steps
Orlov [11]
39x^3 = 13*3*x*x*x

-6x^2 = 2*3*x*x*-1

-3x    = 3*x*-1

so in all these factorizations, 3*x is common. so 3x is the common factor.

by seperating the common factor,

3x(13x^2 - 2x-1)

will be the factorization.


   xy + 5x - 5y - 25

=x (y+5) -5 (y+5)
=(x-5) (y+5)

hope I helped ya!!!
8 0
3 years ago
Help with this one plz!
Alex17521 [72]
What do you need help with?
3 0
3 years ago
Which of the following is equal to the rational expression when x does not equal 3 or 1 x^2-9/(x-1)(x-3)
yuradex [85]

Answer:

b.  \frac{x+3}{x-1}

Step-by-step explanation:

Given expression is:

\frac{x^{2}-9 }{(x-1)(x-3)}

Let us factorize the numerator using the formula:

a^{2} -b^{2} =(a+b)(a-b)

\frac{(x+3)(x-3)}{(x-1)(x-3)}

Since x ≠ 3, let us cancel the common factor x - 3 in the numerator and in the denominator.

So, \frac{x^{2}-9 }{(x-1)(x-3)} =\frac{x+3}{x-1}

7 0
4 years ago
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