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2 years ago

NEED Help! 111=14g and also 13.65=h + 4.88

Mathematics

1 answer:

crimeas [40]2 years ago

3 0

Answer:

In this question if g and h is constant then;

111 = 14g

14g = 111

g = 111/14

g = 27.7 ~ 28

And also,

13.65 = h + 4.88

h + 4.88 = 13.65

h = 13.65 - 4.88

h = 8.77

Hope it helps!

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3 years ago

Solve the system of linear equations by substitution.

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Answer:

Answer:

x= 29/11 or y= 25/11

Step-by-step explanation:

2x - y= 3 ...........equation 1

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Consider the following function. f(x) = 9 − x2/3 Find f(−27) and f(27). f(−27) = f(27) = Find all values c in (−27, 27) such tha

oksano4ka [1.4K]

I guess the function is $f(x)=9-x^{2/3}$ . Then $f(-27)=0$ and $f(27)=0$ .

The derivative is $f'(x)=-\dfrac23 x^{-1/3}$ , but there is no $c$ such that

$-\dfrac23c^{-1/3}=0$

This doesn't contradict Rolle's theorem because $f'(0)$ does not exists. In other words, $f$ is not differentiable on (-27, 27), so the conditions of Rolle's theorem are not met. (Looks like that would be the last option, or the second to last option if the last one is "Nothing can be concluded")