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MatroZZZ [7]
3 years ago
10

________ reaction time involves selecting a specific and correct response from several choices when presented with several diffe

rent stimuli.
Physics
1 answer:
notsponge [240]3 years ago
4 0
The answer would be complex reaction time
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Where can you find the neutrons of an atom? in the nucleus with the protons orbiting the nucleus In the nucleus with the electro
cricket20 [7]

Answer:

Nuclease is the answer I know

I hope this is the answer

3 0
3 years ago
Billiard ball A strikes another ball B of the same mass, which is at rest, such that after the impact they move at angles ΘA and
Drupady [299]

Answer:

7.6427m/s

Explanation:

Given:v_a=4.7m/s, \theta_a=33.0\textdegree and \ v_b=4.5m/s

#Applying the conservation of momentum along the x-axis:mv_i=mv_acos\theta_a+mv_bcos\theta_b

#And along y-axis:

0=-sin\theta_a+mv_bsin\theta_b

#Solving  for \theta_b:

sin\rheta_b=\frac{v_a}{v_b}sin\theta_a=4.7/4.5\times sin33.0\textdegree\\=0.5688\\\therefore \theta_b=34.67\textdegree

#By substitution in the x-axis equation:

v_i=4.7cos 33.0\textdegree +4.5cos 34.67\textdegree\\=7.6427m/s

Hence the original speed of the ball before impact is 7.6427m/s

4 0
3 years ago
The figure below shows a combination of capacitors. Find (a) the equivalent capacitance of combination, and (b) the energy store
velikii [3]

Answer:

A) C_{eq} = 15 10⁻⁶  F,  B)   U₃ = 3 J,  U₄ = 0.5 J

Explanation:

In a complicated circuit, the method of solving them is to work the circuit in pairs, finding the equivalent capacitance to reduce the circuit to simpler forms.

In this case let's start by finding the equivalent capacitance.

A) Let's solve the part where C1 and C3 are. These two capacitors are in serious

         \frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_3}            (you has an mistake in the formula)

         \frac{1}{C_{eq1}} = (\frac{1}{30} + \frac{1}{15}) \  10^{6}

         \frac{1}{C_{eq1}} = 0.1   10⁶

         C_{eq1} = 10 10⁻⁶ F

capacitors C₂, C₄ and C₅ are in series

          \frac{1}{C_{eq2}} = \frac{1}{C_2} + \frac{1}{C_4} + \frac{1}{C_5}

          \frac{1}{C_{eq2} }  = (\frac{1}{15} + \frac{1}{30} +   \frac{1}{10} ) \ 10^6

          \frac{1}{C_{eq2} } = 0.2 10⁶

          C_{eq2} = 5 10⁻⁶ F

the two equivalent capacitors are in parallel therefore

          C_{eq} = C_{eq1} + C_{eq2}

          C_{eq} = (10 + 5) 10⁻⁶

          C_{eq} = 15 10⁻⁶  F

B) the energy stored in C₃

The charge on the parallel voltage is constant

is the sum of the charge on each branch

         Q = C_{eq} V

         Q = 15 10⁻⁶ 6

         Q = 90 10⁻⁶ C

the charge on each branch is

         Q₁ = Ceq1 V

         Q₁ = 10 10⁻⁶ 6

          Q₁ = 60 10⁻⁶ C

         Q₂ = C_{eq2} V

         Q₂ = 5 10⁻⁶ 6

         Q₂ = 30 10⁻⁶ C

now let's analyze the load on each branch

Branch C₁ and C₃

           

In series combination the charge is constant    Q = Q₁ = Q₃

          U₃ = \frac{Q^2}{2 C_3}

          U₃ =\frac{ 60 \ 10^{-6}}{2 \ 10 \ 10^{-6}}

          U₃ = 3 J

In Branch C₂, C₄, C₅

since the capacitors are in series the charge is constant Q = Q₂ = Q₄ = Q₅

          U₄ = \frac{30 \ 10^{-6}}{ 2 \ 30 \ 10^{-6}}

          U₄ = 0.5 J

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Explanation:

Agno3

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Which statement describes a step-down transformer?
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The primary coil has more turns than the secondary coil. so D.
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3 years ago
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