Answer:
32 cm³
Explanation:
The given gas data are;
The relative density of oxygen = 16
The relative density of carbon dioxide = 12
The time it takes 25 cm³ of carbon dioxide to effuse out = 75 seconds'
The duration of effusion of the oxygen = 96 seconds
The rate of effusion of carbon dioxide, R1 = 25 cm³/(75 sec) = (1/3) cm³/sec
According to Graham's law of diffusion and effusion of a gas, we have;

Therefore, we have;


The volume of effusion = The rate of effusion × Time
The volume of the oxygen that will effuse in 96 seconds is given as follows;
The rate of effusion of a gas × Time
V = The rate of effusion of oxygen × Time = (1/3) cm³/sec × 96 sec = 32 cm³
The volume of oxygen that will effuse in 96 seconds, V = 32 cm³.
Answer:
A soma dos dois tipos de energia, potencial e cinética, resultam na energia mecânica. Ou seja, ambas compõe a energia mecânica.
Answer:

Explanation:
We have to many data in different system, so we need transform everything to SI, that is

When we have all this values in SI apply a Energy Balance Equation,
![\dot{Q}_{cv}-\dot{W}_{cv}+\dot{m}[(h_1-h_2)+(\frac{V_1^2-V_2^2}{2})+g(z_1-z_2)]=0](https://tex.z-dn.net/?f=%5Cdot%7BQ%7D_%7Bcv%7D-%5Cdot%7BW%7D_%7Bcv%7D%2B%5Cdot%7Bm%7D%5B%28h_1-h_2%29%2B%28%5Cfrac%7BV_1%5E2-V_2%5E2%7D%7B2%7D%29%2Bg%28z_1-z_2%29%5D%3D0)
Solving for V_2

From the table of gas properties we calculate for
and 


For T_2;

Substituting in equation for V_2


Mass of cat = 10 lb
1 lb = 0.454 kg
So mass of cat is 4.54 kg
Number of tablets given to cat

Each tablet has 6 mg of drug
Total drug given to cat


Now dose given to cat in mg/kg form


