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3 years ago

What is the average speed of an object travels 60 meters in 3 seconds?

Physics

1 answer:

Solnce55 [7]3 years ago

7 0

Answer:

20 metres per second

Explanation:

60/3

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Calculate the magnitude of the effort in the given

Otrada [13]

Moment = Force x Distance from pívot
500x0.5=2.5 x effort
250= 2.5 x effort
effort = 250/2.5= 100N

8 0

3 years ago

The hydraulic oil in a car lift has a density of 8.30 102 kg/m³. The weight of the input piston is negligible. The radii of the

denpristay [2]

Answer:

(a) $F_i=68.58\ N$

(b) $F_i=69.903\ N$

Explanation:

Given:

density of hydraulic oil, $\rho=830\ kg.m^{-3}$

radius of input piston, $r_i=6.3\times 10^{-3}\ m$

radius of output plunger, $r_o=0.125\ m$

force to be supported, $F_o=27000\ N$

(a)

Condition:The bottom surfaces of piston and plunger at the same level.

According to Pascal's law the pressure of a fluid is exerted equally in all directions against the walls of its container.

Mathematically:

$\frac{F_i}{A_i} =\frac{F_o}{A_o}$

putting respective values

$\frac{F_i}{\pi\times r_i^2} =\frac{27000}{\pi\times r_o^2}$

$\frac{F_i}{\pi\times (6.3\times 10^{-3})^2} =\frac{27000}{\pi\times 0.125^2}$

$F_i=68.58\ N$

(b)

Condition:The bottom surface of the output plunger is 1.30 m above that of the input piston.

Given:

$h=1.3\ m$

Now,

$P_i=P_o+\rho.g.h$

$\frac{F_i}{\pi\times (6.3\times 10^{-3})^2} =\frac{27000}{\pi\times 0.125^2} +830\times 9.8\times 1.3$

$F_i=69.903\ N$

7 0

3 years ago

A particle has a de Broglie wavelength of 2.1 × 10-10m. Then its kinetic energy increases by a factor of 3. What is the particle

svlad2 [7]

Answer:

$\lambda' =1.21\times 10^{-10}\ m$

Explanation:

given,

de broglie wavelength of the particle = 2.1 × 10⁻¹⁰m

Kinetic energy increase factor = 3

de broglie wavelength of new particle = ?

we know,

$P = \dfrac{h}{\lambda}$

Kinetic energy

$K =\dfrac{p^2}{2m}$

$K =\dfrac{h^2}{2m\lambda^2}$ ...........(1)

Kinetic energy of other particle

$3K =\dfrac{h^2}{2m\lambda'^2}$ ............(2)

dividing equation (1)/(2)

$\dfrac{1}{3} =\dfrac{\lambda'^2}{\lambda^2}$

$\lambda' = \dfrac{\lambda'}{\sqrt{3}}$

$\lambda' = \dfrac{2.1\times 10^{-10}}{\sqrt{3}}$

$\lambda' =1.21\times 10^{-10}\ m$

6 0

3 years ago

In one to two sentences, explain why electromagnetic radiation can be modeled as both a wave and a particle.

kirill115 [55]

Answer:

The answer is below!!

Explanation:

Electromagnetic radiation (e.g., radio, microwaves, light) can be modeled as a wave of changing electric and magnetic fields or as particles called photons. The wave model is useful for explaining many features of electro-magnetic radiation, and the particle model explains other features.

Hope I Helped!!

4 0

3 years ago

How much kinetic energy will an electron gain if it accelerates through a potential difference of 23,000 volts in a cathode ray

Sauron [17]

Answer:

3.68x10-15 J

Explanation:

I hope this is the right answer sorry if im wrong

8 0

2 years ago