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kondor19780726 [428]

2 years ago

13

Choose the point-slope form of the equation below that represents the line that passes through the point (-1, 6) and has a slope

of -3.
y - 6 = -3x - 3
y - 6 = -3(x + 1)
y = -3x + 3
3x + y = 3

1 answer:

alekssr [168]2 years ago

8 0

For an eqtuaion wih slope m and goes through point (x1,y1)
equation is
y-y1=m(x-x1)

so
point (-1,6)
slope=-3
y-6=-3(x-(-1))
y-6=-3(x+1)

2nd one

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Step-by-step explanation:

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2 years ago

Solve these linear equations by Cramer's Rules Xj=det Bj / det A:

timurjin [86]

Answer:

(a) $x_1=-2,x_2=1$

(b) $x_1=\frac{3}{4} ,x_2=-\frac{1}{2} ,x_3=\frac{1}{4}$

Step-by-step explanation:

(a) For using Cramer's rule you need to find matrix $A$ and the matrix $B_j$ for each variable. The matrix $A$ is formed with the coefficients of the variables in the system. The first step is to accommodate the equations, one under the other, to get $A$ more easily.

$2x_1+5x_2=1\\x_1+4x_2=2$

$\therefore A=\left[\begin{array}{cc}2&5\\1&4\end{array}\right]$

To get $B_1$ , replace in the matrix A the 1st column with the results of the equations:

$B_1=\left[\begin{array}{cc}1&5\\2&4\end{array}\right]$

To get $B_2$ , replace in the matrix A the 2nd column with the results of the equations:

$B_2=\left[\begin{array}{cc}2&1\\1&2\end{array}\right]$

Apply the rule to solve $x_1$ :

$x_1=\frac{det\left(\begin{array}{cc}1&5\\2&4\end{array}\right)}{det\left(\begin{array}{cc}2&5\\1&4\end{array}\right)} =\frac{(1)(4)-(2)(5)}{(2)(4)-(1)(5)} =\frac{4-10}{8-5}=\frac{-6}{3}=-2\\x_1=-2$

In the case of B2, the determinant is going to be zero. Instead of using the rule, substitute the values of the variable $x_1$ in one of the equations and solve for $x_2$ :

$2x_1+5x_2=1\\2(-2)+5x_2=1\\-4+5x_2=1\\5x_2=1+4\\ 5x_2=5\\x_2=1$

(b) In this system, follow the same steps,ust remember $B_3$ is formed by replacing the 3rd column of A with the results of the equations:

$2x_1+x_2 =1\\x_1+2x_2+x_3=0\\x_2+2x_3=0$

$\therefore A=\left[\begin{array}{ccc}2&1&0\\1&2&1\\0&1&2\end{array}\right]$

$B_1=\left[\begin{array}{ccc}1&1&0\\0&2&1\\0&1&2\end{array}\right]$

$B_2=\left[\begin{array}{ccc}2&1&0\\1&0&1\\0&0&2\end{array}\right]$

$B_3=\left[\begin{array}{ccc}2&1&1\\1&2&0\\0&1&0\end{array}\right]$

$x_1=\frac{det\left(\begin{array}{ccc}1&1&0\\0&2&1\\0&1&2\end{array}\right)}{det\left(\begin{array}{ccc}2&1&0\\1&2&1\\0&1&2\end{array}\right)} =\frac{1(2)(2)+(0)(1)(0)+(0)(1)(1)-(1)(1)(1)-(0)(1)(2)-(0)(2)(0)}{(2)(2)(2)+(1)(1)(0)+(0)(1)(1)-(2)(1)(1)-(1)(1)(2)-(0)(2)(0)}\\ x_1=\frac{4+0+0-1-0-0}{8+0+0-2-2-0} =\frac{3}{4} \\x_1=\frac{3}{4}$

$x_2=\frac{det\left(\begin{array}{ccc}2&1&0\\1&0&1\\0&0&2\end{array}\right)}{det\left(\begin{array}{ccc}2&1&0\\1&2&1\\0&1&2\end{array}\right)} =\frac{(2)(0)(2)+(1)(0)(0)+(0)(1)(1)-(2)(0)(1)-(1)(1)(2)-(0)(0)(0)}{4} \\x_2=\frac{0+0+0-0-2-0}{4}=\frac{-2}{4}=-\frac{1}{2}\\x_2=-\frac{1}{2}$

$x_3=\frac{det\left(\begin{array}{ccc}2&1&1\\1&2&0\\0&1&0\end{array}\right)}{det\left(\begin{array}{ccc}2&1&0\\1&2&1\\0&1&2\end{array}\right)}=\frac{(2)(2)(0)+(1)(1)(1)+(0)(1)(0)-(2)(1)(0)-(1)(1)(0)-(0)(2)(1)}{4} \\x_3=\frac{0+1+0-0-0-0}{4}=\frac{1}{4}\\x_3=\frac{1}{4}$

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sveta [45]

Answer:

6) 15

7)5

8)120 degrees

9)60 degrees

10)9

Step-by-step explanation:

GHIJ is a parallelogram.

Opposite sides of a parallelogram are congruent.

3y - 1 = 2y + 1

3y - 2y = 1 + 1

y = 2

Opposite sides of a parallelogram are congruent.

4x + 3 = x + 12

4x - x = 12 - 3

3x = 9

x = 9/3

x = 3

6)GH = ?

GH = 4x + 3

GH = 4(3) + 3

= 12 + 3

= 15

therefore, GH = 15

7) HI = ?

HI = 2y + 1

= 2(2) + 1

= 4 +1

= 5

therefore, HI = 5

Opposite angles of a parallelogram are equal.

8) m(angle I) = 120 degrees...... (given)

therefore, measure of angle G = measure of angle I

therefore, m(angle G) = 120 degrees

Consecutive angles of a parallelogram are supplementary.

9) m(angle I) + m(angle J) = 180 degrees

120 + m (angle J) = 180

m(angle J) = 180 - 120

= 60 degrees.

The diagonals of a parallelogram bisect each other.

10) JK = 9 .........( given)

JK = HK

therefore, HK = 9

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2 years ago

What would be the exact side length of a square with the area of 8 m2

Paraphin [41]

Answer:

2*square root of 2

Step-by-step explanation:

The square root of 8 is equal to 2*square root of 2

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2 years ago

URGENT! PLS ANSWER QUICK!!!!!!!!

skad [1K]

Since the lines have the same slopes, hence they are parallel lines

<h3>How to determine the relationship between lines</h3>

We can determine the relations by knowing the slopes of the line

For the line with coordinates (9, –5) and (5, –2)

Slope = -2+5/5-9
Slope = -3/4

For the line with coordinates (–4, –2) and (–8, 1)

Slope = 1+2/-8+4
Slope = -3/4

Since the lines have the same slopes, hence they are parallel lines

Learn more on parallel lines here: brainly.com/question/16742265

#SPJ1

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1 year ago