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Hatshy [7]
3 years ago
8

How many pounds of Brazilian coffee costing $ 6 per pound must be mixed with 27 lbs of Columbian coffee costing $ 4 per pound to

produce a mixture costing $ 4.5 per pound.
Mathematics
1 answer:
grigory [225]3 years ago
8 0

Answer:

11 2/3 pounds.

Step-by-step explanation:

Let x pounds be the amount in pounds of Brazilian coffee.

x + 27  is the amount of coffee in lbs after the mixing.

So ,working in  values of dollars, we have:

6x + 4*27 = 4.5(x + 27)

6x + 104 = 4.5x + 121.5

1.5x = 121.5 - 104 = 17.5

x = 17.5/1.5 = 11 2/3 pounds answer

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Lunna [17]

Let's see what to do buddy...

_________________________________

Step (1)

We know that the sum of the interior angles of any n-sided figure is obtained from the following equation :

(n - 2) \times 180

Our figure has 5 sides ;

So , sume the interior angles of it equals :

(5 - 2) \times 180 = 3 \times 180 = 540 \\

_________________________________

Step (2)

First look at the photo which I post.

According it we have :

(180 - x) + 120 + 85 + (2x - 10) + 90 = 540 \\

2x - x + 475 - 10 = 540

x + 465 = 540

Subtract the sides of the equation minus 465 :

x = 540 - 465

x = 75

_________________________________

And we're done.

Thanks for watching buddy good luck.

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