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Dahasolnce [82]
3 years ago
11

a compys quality control department found an average 5 defective models for every 1000 models that were checked. If the company

produced 60,000 models in a year, how many if them would be expected to be in working order?
Mathematics
1 answer:
3241004551 [841]3 years ago
6 0
The best thing to do is to found out the percentage that is faulty. 1% is equal to 10 faulty products, therefore, 0.5% is equal to 5. In order to out how many there are in 60,000, you need to simply multiply 5 by 60, which is 300. Therefore, 300 are faulty. Hope this helps :)
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F(x)=x what is the equation of the new function shift 8 units left shift 3 units down
nasty-shy [4]
Think of the equation of a linear function:  
Recall y = mx + b   for vertical shifts, we just add or subtract from 'b' and that will move the line up or down accordingly.. However, for horizontal shifts, we will need to add or subtract from 'x'.  Note that the slope or 'm' stays the same for each type of shift.  

Now that we know how the shifts occur, we might consider a different form of the equation for a linear function:  y = a(x - h) + k  here the 'a' is just our slope, 'k' is our original y intercept, and 'h' will represent the amount of horizontal shift.  

So to get the desired transformations of a horizontal shift to the left of 8 and a vertical shift of down 3 from our original function y = x, we can make the following changes:   y = (x + 8) - 3  Now you might be confused with how we got the 'x + 8'..   Let's consider values of 'h'.  For positive values of h, the result will be a shift to the right and for negative values of h the result will be a shift to the left.  So since we want a shift to the left we need to use a '-8' and when we substitute that into our new form, y = (x - h) + k you can see the sign change.  

Now we can simplify of course and get the final equation: y = x + 5 or in function form f(x) = x + 5
4 0
3 years ago
Combine as indicated by the signs. 4/ y^2-9 + 5/y+3
natka813 [3]
\frac{4}{y^{2}-9 } + \frac{5}{y+3} = \frac{4}{(y-3)(y+3) } + \frac{5}{y+3}= \frac{4}{(y-3)(y+3) } + \frac{5(y-3)}{(y-3)(y+3)}=
\\ \\=\frac{4}{(y-3)(y+3) } + \frac{5y-15}{(y-3)(y+3)}= \frac{5y-11}{(y-3)(y+3)}=\frac{5y-11}{y^{2}-9}

8 0
3 years ago
p is a polynomial of degree 5. p has roots of multiplicity 2 at t=4 and t=0, a root of multiplicity 1 at t=-4, and p(1)=2025. Fi
DENIUS [597]
P(x) = (x^2)(x - 4)^2(x + 4) + some constant(b)
2025 = (1^2)(1 - 4)^2(1 + 4) + b
2025 = 45 + b
b = 1980

Complete Equation:

p(x) = (x^2)(x - 4)^2(x +4) + 1980

or expanded form

p(x) = x^5 - 4x^4 - 16x^3 + 64x^2 + 1980
5 0
2 years ago
Help I’m struggling badly in math
Fynjy0 [20]

Answer:

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Step-by-step explanation:

hope that helped.

5 0
2 years ago
When Michael was 10 years old, Sam was 14. Sam is now 28 and Michael is 24.​
SpyIntel [72]

Answer:

4 years difference

Step-by-step explanation:

6 0
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