Answer:
The pseudocode is as follows:
Input SalesAmount
Input CommissionRate
CommissionEarned= SalesAmount * (CommissionRate/100)
Print CommissionEarned
Explanation:
This gets input for SalesAmount
Input SalesAmount
This gets input for CommissionRate
Input CommissionRate
This calculates the CommissionEarned
CommissionEarned= SalesAmount * (CommissionRate/100)
This prints the calculated CommissionEarned
Print CommissionEarned
Answer:
hello below is missing piece of the complete question
minimum size = 0.3 cm
answer : 0.247 N/mm2
Explanation:
Given data :
section span : 10.9 and 13.4 cm
minimum load applied evenly to the top of span : 13 N
maximum load for each member ; 4.5 N
lets take each member to be 4.2 cm
Determine the max value of P before truss fails
Taking average value of section span ≈ 12 cm
Given minimum load distributed evenly on top of section span = 13 N
we will calculate the value of by applying this formula
= = 1.56 * 10^-5
next we will consider section ; 4.2 cm * 0.3 cm
hence Z (section modulus ) = BD^2 / 6
= ( 0.042 * 0.003^2 ) / 6 = 6.3*10^-8
Finally the max value of P( stress ) before the truss fails
= M/Z = ( 1.56 * 10^-5 ) / ( 6.3*10^-8 )
= 0.247 N/mm2
Answer:
Being a good friend and actually helping others and participate in every way possible
Explanation:
Answer:
7ft (2.13 m).
Explanation:
From the question above, the following parameters/data are given; the room dimension = 12 ft × 18 ft (∼3.7 m × ∼5.5 m), the floor-to-ceiling height = 9 ft (2.8 m) and the spacing ratio for the luminaire is 1:0.
Note that, we are not given the value or data for the height of the plane, therefore, we will make an assumption that the height of the plane = 2ft.
Hence, the work plane to luminaire distance = (9 - 2)ft = 7ft (2.13 m).
So, the maximum distance that the luminaires can be separated and achieve uniform illuminance is;
= the work plane to luminaire distance × spacing ratio for the luminaire.
= 7ft (2.13 m) × 1 = 7ft (2.13 m).
Thus, the maximum distance that the luminaires can be separated and achieve uniform illuminance is 7ft (2.13 m).
D marketing because he’s advertising ski equipment to buy