Answer:
230.51 m
Explanation:
Pb = 695 mmHg
Pt = 675 mmHg
Pb - Pt = 20 mmHg
Calculate dP:
dP = p * g * H = (13600)*(9.81)*(20/1000) = 2668.320 Pa
Calculate Height of building as dP is same for any medium of liquid
dP = p*g*H = 2668.320
H = 2668.32 / (1.18 * 9.81) = 230.51 m
Answer:
lubricating all moving parts in the engine
Explanation:
like the pistons, pushrods, and the crank
Answer:
- using System;
- public class Program
- {
- public static void Main()
- {
- Console.WriteLine("Enter number of students: ");
- int num = Convert.ToInt32(Console.ReadLine());
- string [] firstName = new string[num];
- string [] lastName = new string[num];
-
- for(int i=0 ; i < num; i++){
- Console.WriteLine("Enter first name: ");
- firstName[i] = Console.ReadLine();
-
- Console.WriteLine("Enter last name: ");
- lastName[i] = Console.ReadLine();
- }
-
- for(int j=0; j < num; j++){
- Console.WriteLine(lastName[j] + "," + firstName[j]);
- }
- }
- }
Explanation:
Firstly, prompt user to enter number of student to be stored (Line 6- 7). Next, create two array, firstName and lastName with num size (Line 8-9).
Create a for-loop to repeat for num times and prompt user to enter first name and last name and then store them in the firstName and lastName array, respectively (Line 11 - 17).
Create another for loop to traverse through the lastName and firstName array and display the last name and first name by following the format given in the question (Line 19 - 21).
The work done by a 10 HP motor when it raises a 1000 Newton weight at a vertical distance of 5 meters is <u>5kJ</u>.
Define work. Explain the rate of doing work.
Work is <u>the energy that is moved to or from an item by applying force along a displacement</u> in physics. For a constant force acting in the same direction as the motion, work is <u>easiest expressed as the product of </u><u>force </u><u>magnitude and distance traveled</u>.
Since the <u>force </u><u>transfers one unit of energy for every unit of </u><u>work </u><u>it performs</u>, the rate at which work is done and energy is used are equal.
Solution Explained:
Given,
Weight = 1000N and distance = 5m
A/Q, the work here is done in lifting then
Work = (weight) × (distance moved)
= 1000 X 5
= 5000Nm or 5000J = 5kJ
Therefore, the work done in lifting a 1000 Newton weight at a vertical distance of 5 meters is 5kJ.
To learn more about work, use the link given
brainly.com/question/25573309
#SPJ9
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