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Anit [1.1K]
3 years ago
15

Which expression is equivalent to the expression below

Mathematics
1 answer:
musickatia [10]3 years ago
3 0

9.2 + (-8) = 1.2

-(-7/6)= 1.16


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8) What is the common ratio for this sequence?
Naddika [18.5K]

Step-by-step explanation:

it will 2.5 this is right answer option D

6 0
3 years ago
The moon is approximately 240,000 miles from the earth. What is the distance written in scientific notation?
-BARSIC- [3]
Hello there!

Scientific notation is when the number is between 0 and 10 times 10 to a power.
In this case we'd get 2.4 x 10^{5}.

Hope This Helps You!
Good Luck :)
6 0
3 years ago
Read 2 more answers
Suppose that a researcher is designing a survey to estimate the proportion of adults in your state who oppose a proposed law tha
irinina [24]

Answer:

n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

Solution to the problem

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

The margin of error desired for this case is ME= \pm 0.02 equivalent to 2% points

For this case we need to assume a confidence level, let's assume 95%. And since we don't have prior estimation for the population proportion of interest the best value to do an approximation is \hat p =0.5

In order to find the critical value we need to take in count that we are finding the margin of error for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.96  

Now we have all the values needed and if we replace into equation (b) we got:

n=\frac{0.5 (1-0.5)}{(\frac{0.02}{1.96})^2}= 2401

So without prior estimation for the population proportion, using a confidence level of 95% if we want a margin of error about 2% we need al least a sample size of 2401.

5 0
4 years ago
1. {26, 69, 30, 27, 19, 54, 27}<br><br> Mean: <br> , Median: <br> , Mode: <br> , Range:
den301095 [7]

Answer:

Mean:36

Median:27

Mode:27

Range:50

Step-by-step explanation:

Mean: 19+26+27+27+30+53+69/7=36

Median: The middle number in the sequence when arranged in ascending order which is 27

Mode: The number that appeared more than others which is 27

Range: This is the difference between the largest number and the lowest number in the sequence which is 50.

IF THIS HELPS PLEASE MARK ME AS BRAINLIEST

5 0
2 years ago
Two drivers, Alison and Kevin, are participating in a drag race. Beginning from a standing start, they each proceed with a const
Vilka [71]

Answer:

Alison wins against Kevin by 0.93 s

Step-by-step explanation:

Alison covers the last 1/4 of the distance in 3 seconds, at a constant acceleration a_a, we have the following equation of motion

s/4 = a_at_a^2/2

where s (m) is the total distance, ta = 3 s is the time

s = 4a_a3^2/2 = 18a_a

a_a = s/18

Similarly, Kevin overs the last 1/3 of the distance in 4 seconds, at a constant acceleration a_k, we have the following equation of motion:

s/3 = a_kt_k^2/2

tk = 4 s is the time

s = 3a_k4^2/2 = 24a_k

a_k = s/24

Since a_a = s/18 we can conclude that a_a > a_k, so Alison would win.

The time it takes for Alison to cover the entire track

s = a_aT_a^2/2

T_a^2 = 2s/a_a = 2s/(s/18) = 36

T_a = \sqrt{36} = 6 s

The time it takes for Kevin to cover the entire track

s = a_kT_k^2/2

T_k^2 = 2s/a_k = 2s/(s/24) = 48

T_a = \sqrt{48} = 6.93 s

So Alison wins against Kevin by 6.93 - 6 = 0.93 s

4 0
3 years ago
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