Sarah had some cookies. She then gave her friend, Mike, eight cookies.
Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
The work is down below. your answer is m=8.
If a(n) = (39n^4 -506n^3 + 2341n^2 - 4610n + 3416) / 8 then
<span>a(1) = 85 </span>
<span>a(2) = 17 </span>
<span>a(3) = 19 </span>
<span>a(4) = 4 </span>
<span>a(5) = 2</span>
