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Arte-miy333 [17]
3 years ago
15

Someone please help on this

Physics
2 answers:
liq [111]3 years ago
5 0
I think it is A. Newton's first law being an object in motion stays in motion unless acted upon by another force
blsea [12.9K]3 years ago
3 0

First


Norton's first law basically says an object will stay the same unless another force acts upon it.

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Suppose a piece of food is on the edge of a rotating microwave oven plate. Does it experience nonzero tangential acceleration, c
Rus_ich [418]

Answer:

Explanation:

(a) When the plate starts to spin:

Its angular velocity increases, so the angular acceleration is non zero. As the direction of velocity keeps on changing every instant so the linear acceleration is also non zero.

(b) When the plate rotates at constant angular velocity:

Its angular velocity is constant so the angular acceleration is zero. As the direction of velocity keeps on changing every instant so the linear acceleration is also non zero.

(c) When the plate sows to halt:

Its angular velocity decreases, so the angular acceleration is non zero( but negative). As the direction of velocity keeps on changing every instant so the linear acceleration is also non zero.

4 0
3 years ago
I'll give 20 points!!!
qwelly [4]

Answer:

Its b)

Explanation:

4 0
3 years ago
according to newton's second law of motion of the net force acting on the object increases while the mass of the object remains
Licemer1 [7]

Answer:

The Acceleration will increase

Explanation:

Newton's Second Law of motion: It states that the rate of change of momentum is directly proportional to the applied force and takes places along the direction of the force.

It can be expressed mathematically as,

F ∝ m(v-u)/t

Where (v-u)/t = a

F  = kma.

F = force, m = mass of the body, a = acceleration, k = constant of proportionality which tend to unity for a unit force, a unit mass, and a unit acceleration.

Therefore,

F = ma.

From the equation above,

If the net force acting on a body increase, while the mass of the body remains constant, the acceleration will also increase.

4 0
3 years ago
A spherical snowball is melting in such a way that its radius is decreasing at rate of 0.1 cm/min. At what rate is the volume of
andrew11 [14]

Answer:

\frac{dV}{dt}=-78,4\pi \frac{cm^{3} }{min}

Explanation:

Knowing that the volume of a sphere is V=(4/3)πr³ and \frac{dr}{dt}=-0.1\frac{cm}{min}

We must find \frac{dV}{dt}=? when r=14cm

V=(4/3)πr³ ⇒

\frac{dV}{dt}=\frac{4}{3}\pi3r^{2}\frac{dr}{dt}\\\frac{dV}{dt}=4\pi r^{2}(-0.1\frac{cm}{min})

and r=14cm then

\frac{dV}{dt}=4\pi(14cm)^{2}(-0.1\frac{cm}{min})\\\frac{dV}{dt}=4\pi196cm^{2}(-0.1\frac{cm}{min})\\\frac{dV}{dt}=-78,4\pi \frac{cm^{3} }{min}

Note: as you can see the relationship of change of r with respect to t is negative because it is a decrease, and also its volume ratio

4 0
4 years ago
Easy physics question help.!!!
stellarik [79]

Answer: This is not easy lol

Explanation:

3 0
3 years ago
Read 2 more answers
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