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vlada-n [284]
4 years ago
8

The centripetal force acting on a satellite in orbit

Physics
2 answers:
krok68 [10]4 years ago
8 0

The centripetal force (of gravity) on a satellite in orbit is an
unbalanced force (because there's no equal force pulling
the satellite away from Earth), changes the direction of the
satellite (into a closed orbit instead of a straight line), and
always acts toward the center of whatever curve the satellite
happens to be on at the moment.

AysviL [449]4 years ago
3 0

Answer : (D) " all of the above "

Explanation :

The forces acting on a satellite are Earth's gravitational force and centripetal force. The properties of centripetal force acting on a satellite in orbit are as follows :

(1) It acts as an unbalanced force on the satellite. This is due to the reason that there is no same force present which pulls the satellite away from the earth.

(2) It changes the direction of the satellite. The satellite is revolving with a constant speed while the direction is kept on changing (in a circular motion).

(3) Centripetal force always acts towards the center.

So, the correct option is (D) " all of the above "

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What is neant by velocity ratio of machine is 3 and efficency is 60%​
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Answer:

Velocity ratio of a lever is 3 means distance travelled by effort is 3 times the distance travelled by the load. Efficiency of the pulley is 60%means 40% of the energy is lost in the machine due to the friction

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a 10 uF capacitpr is connected to a 12 V battery till its fully charged. it is then disconnected and to an uncharged 20 uF capac
likoan [24]

Answer:

Explanation:

The charge on 10μF capacitor =  10 x 12 x 10⁻⁶ = 120 μC

when it is connected with 20μF capacitor both acquires common potential whose value is

= 120 x 10⁻⁶ /( 10 +20) x 10⁻⁶ = 4 V.

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An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. how high does it rise (v = 0 cm
Aliun [14]
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3 years ago
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The shortest pipe in a particular organ is 1.23 m.
AVprozaik [17]

Answer:

The 9th harmonic is 1,010.67 Hz.

Explanation:

Given;

length of the pipe, L = 1.23 m

speed of sound at 0°C = 331.5 m/s

A pipe closed at one end is known as a closed pipe;

The wavelength of the sound for the first harmonic is calculated as;

L = Node ------ > Antinode

L = \frac{\lambda }{4} \\\\\lambda = 4L

First harmonic:  F_0 = \frac{V}{\lambda} = \frac{V}{4L}

The wavelength of the sound for the first harmonic is calculated;

L = Node ----> Node + Node ------> Antinode

L = \frac{\lambda}{2} + \frac{\lambda}{4} = \frac{2\lambda+\lambda}{4} = \frac{3\lambda}{4} \\\\\lambda = \frac{4 L}{3}

Second harmonic: F_1 =  \frac{V}{\lambda} = \frac{3V}{4L}

F₁ = 3F₀

The increment from F₀ to F₁ is 1 to 3; (odd number).

(1, 3, 5, 7, 9, 11, 13, 15, 17, 19..... n+2, where n is odd number)

The 9th harmonic = F₈

F₈ = 15F₀

F_8= 17(F_0) = 15 (\frac{V}{4L} )\\\\F_8 = 15(\frac{331.5}{4\times 1.23} )\\\\F_8 = 1,010.67 \ Hz

Therefore, the 9th harmonic is 1,010.67 Hz.

8 0
3 years ago
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Answer:

Explanation:

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W = 12 x 10^-6 J

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4 years ago
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