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sweet [91]
3 years ago
11

Suppose 17% of the listeners of a radio station listen to it while they work. What is the approximate standard deviation of the

proportion for the samples of size 91?
•3.9%
•7.8%
•0.4%
•1.8%
Mathematics
1 answer:
Oksanka [162]3 years ago
7 0

Answer:

The correct answer is 3.9%

Step-by-step explanation:

P : the probability of listening at work, is 17%  or 0.17

Q : the probability of NOT listening at work, is 1 - 0.17, or 83% or 0.83

N : the sample size, is 91

The standard deviation of samples then is

=\sqrt{\frac{P\times Q}{N}} \\\\=\sqrt{\frac{0.17\times 0.83}{91}}\approx 0.0394\\\\\implies \text{Approximate standard deviation percentage = }\text{standard deviation}\times\text{100}\\=0.00394\times 100\\=3.9\%

 So, the correct Option is A. 3.9%

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Step-by-step explanation:

The correlation coefficient is a statistical degree that computes the strength of the linear relationship amid the relative movements of the two variables (i.e. dependent and independent).It ranges from -1 to +1.

The formula to compute correlation between two variables <em>X</em> and <em>Y</em> is:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

The formula to compute covariance is:

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The formula to compute the variances are:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}

Consider the table attached below.

Compute the covariance as follows:

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                 =(5\times 165)-(30\times 25)\\=75

Thus, the covariance is 75.

Compute the variance of X and Y as follows:

V(X)=n\cdot\sum X^{2}-(\sum X)^{2}\\=(5\times 226)-(30)^{2}\\=230\\\\V(Y)=n\cdot\sum Y^{2}-(\sum Y)^{2}\\=(5\times 135)-(25)^{2}\\=50

Compute the correlation coefficient as follows:

r(X, Y)=\frac{Cov(X, Y)}{\sqrt{V(X)\cdot V(Y)}}

            =\frac{75}{\sqrt{230\times 50}}

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Thus, the Pearson's coefficient of correlation between the is 0.700.

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