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max2010maxim [7]
3 years ago
5

If a man runs for an hour and a half at 8 miles an hour due south and then he continues south on an is traveling at 55 miles per

hour for 14 minutes how far did he travel
Mathematics
1 answer:
frozen [14]3 years ago
7 0
8x1.5 = 12 miles 55X(14/60) = approx 13 miles he ran 25 miles
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shutvik [7]
The small triangle and big triangle are similar - this means they have the same angles. So, if you know the ratio of a side of the big triangle (12) to a side of the small triangle inside it (4), you know the ratio of the other sides. In this case, the side ratio (small to big triangle) is 1/3. Thus, the missing side length is 18/3=6.
Brainliest? ;D
7 0
4 years ago
Given the Production Function Q = 72X + 15X 2 - X 3 , where Q =Output and X=Input (5 marks) a) What is the Marginal Product (MP)
rusak2 [61]

Answer:

a.) Marginal Product (MP) = 120

b.) Average Product = 126

c.) At x = 12, the output is maximum.

d.) After 5 levels of inputs diminishing returns set in.

Step-by-step explanation:

Given that,

Q = 72x + 15x² - x³

a.)

Marginal Product is equal to

\frac{dQ}{dx} = 72 + 30x - 3x^{2}

At x = 8

MP = 72 + 30(8) - 3(8)²

     = 72 + 240 - 192

     = 120

∴ we get

Marginal Product (MP) = 120

b.)

Average Product is equals to

= \frac{Q}{x}

= 72 + 15x - x²

At x = 6

Average Product = 72 + 15(6) - 6²

                             = 72 + 90 - 36

                             = 126

∴ we get

Average Product = 126

c.)

For Maximizing Q,

Put \frac{dQ}{dx} = 0

⇒72 + 30x - 3x² = 0

⇒24 + 10x - x² = 0

⇒x² - 10x - 24 = 0

⇒x² - 12x + 2x - 24 = 0

⇒x(x - 12) + 2(x - 12) = 0

⇒(x + 2)(x - 12) = 0

⇒x = -2, 12

As items can not be negative

∴ we get

At x = 12, the output is maximum.

d.)

Now,

For Diminishing Return

\frac{d(MP)}{dx} = \frac{d^{2}Q}{dx^{2} }   < 0

⇒30 - 6x < 0

⇒-6x < -30

⇒6x > 30

⇒x > 5

∴ we get

For x > 5, the diminishing returns set in

i.e.

After 5 levels of inputs diminishing returns set in.

3 0
3 years ago
Will award brainiest to whoever answers and helps, I really need this ;;
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