Answer:
B
Step-by-step explanation:
Perpendicular lines have opposite-reciprocal slopes
So if I had a slope of 2, the perpendicular slope would be -1/2.
Or if I had a slope of -7, the reciprocal is -1/7 and the opposite would be 1/7.
Hope this helps!
No. Because sides JM and KL have different slopes from sides AD and BC .
The formula of a slope:
For AD:
We have the points A(2, -2) and D(1, -4). Substitute:
For JM:
We have the points J(4, -4) and M(2, -9). Substitute:
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Another argument.
No. Because the MJ is not twice as long as AD.
The formula of the length of a segment:
The length of AD:
The length of MJ:
1) He worked 4 hours leaving 6 more hours for him.
rate for A alone 6 baker
rate for A & B together 4
1/a+1/b=1/x
1/6+1/b=1/4
1/b=1/4-1/6
1/b=6/24-4/24
1/b=2/24
1/b=1/12
b=12
rate for wife alone 12 hours for the remaining 6 hours
check
1/6+1/12=1/4
12/72+6/72=1/4
18/72=1/4
ok
codewa
But we want to know how long it would have taken her for the whole job not just part of it
he works twice as fast as she does so the job that takes him 10 hours alone would take her 20 hours alone.
2) jessica and cynthia work in a pet shop.
it takes jessica 6 hours to groom all the pets but cynthia needs 8 hours to groom them.
if jessica starts to groom 1 hour before cynthia joins, how long will it take them to finish?
:
let t = time it takes them to finish (C's working time)
then
t+1 = J's working time
let 1 = completed job (all pets groomed)
:
A shared work equation, each does a fraction of the job, the two fractions add up to 1
%28%28t%2B1%29%29%2F6 + t%2F8 = 1
Multiply by the least common multiple of 6 and 8, 24. cancel the denominators
4(t+1) + 3t = 24
4t + 4 + 3t = 24
4t + 3t = 24 - 4
7t = 20
t = 20/7
t = 26%2F7 hrs, which is: 2 + 6%2F7*60 = 2 hrs 51.43 min to finish the job
3) math club takes 40 minutes
science takes 50 minutes.
rate * time = quantity
quantity = 1 set up of the tables.
rate for math club is 1/40 of all the tables in 1 minute.
rate for science club is 1/50 of all the tables in 1 minute.
math club works for 10 minutes.
rate * time = quantity
1/40 * 10 = 10/40 = 1/4 of the tables are already set up by the math club.
there are 3/4 of the tables that still need to be set up.
rate * time = quantity
the rates of the math club and the science club are additive.
(1/40 + 1/50) * time = 3/4 of the tables that still need to be set up.
common denominator is 200.
(5/200 + 4/200) * time = 3/4.
9/200 * time = 3/4
time = 3/4 * 200/9 = 600 / 36 = 16 and 2/3 minutes.
total time required is 10 + 16 + 2/3 minutes = 26 + 2/3 minutes.
how to check.
10 minutes is used to do 1/4 of the tables.
16 + 2/3 minutes is used to do the remaining 3/4 of the tables.
combined rate of math and science club is 9/200 of the tables in 1 minute.
math club rate of 1/40 * 10 = 10/40 = 1/4 of the tables.
combine rate of 9/200 * (16 + 2/3) = 9/200 * 50/3 = 450/600 = 9/12 = 3/4 of the tables.
1/4 + 3/4 = 1 = all of the tables.
Answer:
Step-by-step explanation:
(find the percent by multiplying the percentage, .45, by the total number of shoes = 18 shoes)
% = 45%
p = 18
w = 40
(i did 100/40 which equals to 2.5 then multiplied 2.5 by the numerator so the numerator and denominator would both be equivelant.)
18/40 = 45/100
(multiply the whole (40) by the decimal value (.45) which is equal to 18)
40 x .45 = 18
(answer)
If Ms. M has 40 pairs of shoes, 18 of those shoes are sneakers.
Answer:
720.8
Step-by-step explanation:
(2.6 × 106) + (4.2 × 106)
275.6 + 445.2
720.8
