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2 years ago

2x+3(x-2)-3(x-6) figuring for X

Mathematics

2 answers:

aniked [119]2 years ago

7 0

2x^2-4x+3x-6-3x-18
2x^2-4x-24

x =(2-√52)/2=1-√ 13 = -2.606
x =(2+√52)/2=1+√ 13 = 4.606

emmainna [20.7K]2 years ago

6 0

Answer:

2x+12

Step-by-step explanation:

2x+3(x-2)-3(x-6)

2x+3x-6-3x+18

2x-6+18

2x+12

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dalvyx [7]

Answer with Step-by-step explanation:

We are given that a ball is thrown into the air with velocity

$v=40ft/s$

Height after t seconds is given by

$s(t)=40t-16t^2$

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We know that average velocity= $\frac{ds}{dt}$

Average velocity=v= $\frac{d(40t-16t^2)}{dt}=40-32t$

Substitute t=1 then we get

Average velocity= $40-32(1)=40-32=8 m/s$

Substitute t=2 then

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4 0

2 years ago

Please help!! FAST!!

egoroff_w [7]

Follow the order of operations!!
1. Parentheses
2. Exponents
3. Multiplication
4. Division
5. Addition
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that is in order. follow these and you should figure it out yourself :)

3 0

2 years ago

On April 11, 2012, two earthquakes were measured off the northwest coast of Sumatra. The first had a magnitude of 8.6. The secon

Hoochie [10]

Answer:

Option D. 2.51 is correct.

Step-by-step explanation:

Magnitude of first earthquake = 8.6

Let intensity of first earthquake be x

$Magnitude = \log(\frac{x}{S}),\text{ where S is seismographic factor}\\\\\implies 8.6=\log(\frac{x}{S}).......(1)$

Magnitude of second earthquake = 8.2

Let intensity of second earthquake be y

$Magnitude = \log(\frac{y}{S}),\text{ where S is seismographic factor}\\\\\implies 8.2=\log(\frac{y}{S}).......(2)$

Now, to find the factor by which intensity of first earthquake is greater than intensity of second : we divide equation (1) by equation (2)

$\implies\log(\frac{x}{y})=8.6 - 8.2\\\\\implies \log(\frac{x}{y})=0.4\\\\\implies\frac{x}{y}=10^{0.4}\\\\\implies\frac{x}{y}=2.51$

Hence the required factor is 2.51

Therefore, Option D. 2.51 is correct.

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2 years ago

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natta225 [31]

Answer:

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Step-by-step explanation:

y - y₁ = m(x - x₁)

⇒ y - 0 = -1/2(x - 6)

⇒ y = -1/2x + 3

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Answer:

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Step-by-step explanation:

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