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2 years ago

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20%3F%20over%2011." id="TexFormula1" title="Determine the unknown quantity. Show your work.8 1/2 over 3 2/3 = ? over 11." alt="Determine the unknown quantity. Show your work.8 1/2 over 3 2/3 = ? over 11." align="absmiddle" class="latex-formula">

2 answers:

san4es73 [151]2 years ago

5 0

um approximatly 0.34519202904

Vadim26 [7]2 years ago

5 0

Totally would be 10863628 because it’s just so easy

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-X + 2y = 10<br> -3x+ 6y = 11

Tanzania [10]

Answer:

1. y = 1 /2X +5

Step-by-step explanation:

2. m=1/2

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2 years ago

Help me guys! 50 points!

timama [110]

Answer:

The volume of the irregular figure would be 144 $cm^3$ .

Step-by-step explanation:

If you wish to make the process of calculating the volume easier, you can picture the irregular figure as two rectangular prisms: the large one on the bottom, and the smaller one appearing to protrude from the prism below it. Using this method, you only need to find the volumes of the two rectangular prisms and add the values together to get the volume for the irregular figure. The formula used to find the volume of a rectangular prism is $l*w*h$ , where $l$ , $w$ , and $h$ , represents the length, width, and height of the rectangular prism respectively. Using the formula above, the volume of the larger rectangular prism would be 12 * 3 * 3 = 12 * 9 = 108 $cm^3$ , and the volume of the smaller rectangular prism would be 4 * 3 * 3 = 12 * 3 = 36 $cm^3$ . So the volume of the entire irregular figure would be 108 + 36 = 144 $cm^3$ .

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2 years ago

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If Tom runs 3.5 miles in 29.4 minutes, how many hours would it take him to run 26 miles? Show your work.

Thepotemich [5.8K]

Answer:

Step-by-step explanation:

3.5 miles/(29.4 minutes)

26 miles × (29.4 minutes)/(3.5 miles) = 218.4 minutes

218.4 minutes × (1 hour)/(60 minutes) = 3.64 hours

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2 years ago

The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i

kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

$S=\pi r\sqrt{r^2+h^2}$

and volume,

$V=\frac{1}{3}\pi r^2 h$

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

$f(r,h)=\frac{1}{3}\pi r^2 h$

subject to,

$g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)$

We know for maximum volume $r\neq 0$ . So let $\lambda$ be the Lagranges multipliers be such that,

$f_r=\lambda g_r$

$\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)$

And,

$f_h=\lambda g_h$

$\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}$

$\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)$

Substitute (3) in (2) we get,

$\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)$

$\implies h^2=2r^2$

Substitute this value in (1) we get,

$\pi r\sqrt{h^2+r^2}=8$

$\implies \pi r \sqrt{2r^2+r^2}=8$

$\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252$

Then,

$h=\sqrt{2}(1.21252)\equiv 1.71476$

Hence largest volume,

$V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114$

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3 years ago

Please give me the correct answer

Mashutka [201]

Answer:

1st one

Step-by-step explanation:

Because It is just like a right triangle.

Also, look at how the bird is formed, it looks like a right triangle.

Also, I know it's a right triangle because of the length given.

Hope this helped!

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3 years ago

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