I don’t understand this I tried to do it but still don’t understand help is needed

In factored form please help

Brilliant_brown [7]

Answer:

3rd option

Step-by-step explanation:

$\frac{3x^2-3}{x^2-5x+4}$ ( factorise numerator and denominator )

3x² - 3 ← factor out 3 from each term

= 3(x² - 1²) ← x² - 1 is a difference of squares and factors in general as

a² - b² = (a - b)(a + b)

x² - 1

= x² - 1²

= (x - 1)(x + 1) , then

3x² - 3 = 3²(x - 1)(x + 1) ← in factored form

--------------------------------

x² - 5x + 4

consider the factors of the constant term (+ 4) which sum to give the coefficient of the x- term (- 5)

the factors are - 1 and - 4 , since

- 1 × - 4 = + 4 and - 1 - 4 = - 5 , then

x² - 5x + 4 = (x - 1)(x - 4)

then

$\frac{3x^2-3}{x^2-5x+4}$ = $\frac{3(x-1)(x+1)}{(x-1)(x-4)}$ ← in factored form

3 0

2 years ago

Which one is it i don’t know

matrenka [14]

Answer:

the anwer is

$3f - 9g + 7$

3 0

3 years ago

Does anyone know this?

Darina [25.2K]

2 x 2 x 2 x 3

Because you are multiplying two, four times

6 0

3 years ago

In quadrilateral $ABCD$, we have $AB=3,$ $BC=6,$ $CD=4,$ and $DA=4$.

vampirchik [111]

The triangle inequality applies.

In order for ACD to be a triangle, the length of AC must lie between CD-DA=0 and CD+DA=8.

In order for ABD to be a triangle, the length of AC must lie between BC-AB=3 and BC+AB=9.

The values common to both these restrictions are numbers between 3 and 8. Assuming we don't want the diagonal to be coincident with any sides, its integer length will be one of ...
{4, 5, 6, 7}

8 0

3 years ago

2x-5y+5z=-10<br> 5x-4y+3z=-19<br> X-y+5z=17

yarga [219]

Answer:

x = -125/71 , y = 448/71 , z = 356/71

Step-by-step explanation:

Solve the following system:

{2 x - 5 y + 5 z = -10 | (equation 1)

5 x - 4 y + 3 z = -19 | (equation 2)

x - y + 5 z = 17 | (equation 3)

Swap equation 1 with equation 2: